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Minchanka [31]
4 years ago
10

The product of a number y and 3 is 6

Mathematics
1 answer:
Solnce55 [7]4 years ago
8 0

Answer:

y = 2

Step-by-step explanation

3y=6

Divide both sides by 3

\frac{3y}{3} =\frac{6}{3}

Simplify

y=2

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12/45 =¿ fraccion mixta ,propia o impropia?<br><br> 24/5=¿fraccion mixta,propia o impropia?
Aloiza [94]
12/45 = fracción propia24/5 = fracción impropia
8 0
3 years ago
Find the solution of the system of equations 2x-4y=32 2x-8y=48
Sveta_85 [38]
<span>2x-4y=32
2x-8y=48
--------------subtract
4y = - 16
y  = -4

</span>2x-4y=32 
2x- 4(-4)=32 
2x + 16 = 32
2x = 16
x = 8

answer
(8, -4)
6 0
3 years ago
Read 2 more answers
Find the length of OC.
frosja888 [35]

Answer:

About 8

Step-by-step explanation:

I found this by doing 16 divided by 2 since half of 16 is 8and AC and OC are congruent so I think it is 8.

6 0
4 years ago
Read 2 more answers
1. The sum of first n terms of an arithmetic sequence is 3n²+4n
valentina_108 [34]

Answer:

<h3>           a.  a₁=7,     b.  a_n=7n+1,    c.  a₂₀=141</h3>

Step-by-step explanation:

a.

 a_1=S_1=3\cdot1^2+4\cdot1=3+4=7

b.

   a_1+a_2=S_2\\\\a_1+a_1+d=3\cdot2^2+4\cdot2\\\\7+7+d=3\cdot4+8\\\\14+d=12+8\\\\d=6\\\\\\a_n=a_1+d(n-1)\\\\a_n=7+6(n-1)\\\\a_n=7+6n-6\\\\\underline{a_n=7n+1}

c.

 a_{20}=7\cdot20+1=141

5 0
3 years ago
A theater has a seating capacity of 750 and charges $3 for children, s5 for students, and $7 for adults. At a certain screening
-BARSIC- [3]

Answer:

Between 150 and 450

Step-by-step explanation:

We are going to find the number by resolving  a system of linear equations.

First we write the system equations :

C+S+A=750

Where C : children, S : students and A : adults

The equation represents the ''full attendance''

The second equation :

3C+5S+7A=3450

This equation represents the totaled receipts.

The system :

C+S+A=750\\3C+5S+7A=3450

has the following associated matrix :

\left[\begin{array}{cccc}1&1&1&750\\3&5&7&3450\end{array}\right]

By performing elementary matrix operations we find that the matrix is equivalent to

\left[\begin{array}{cccc}1&0&-1&150\\0&1&2&600\\\end{array}\right]

The new system :

C-A=150\\S+2A=600

Working with the equations :

C = 150 + A\\S = 600-2A

Our solution vector is :

\left[\begin{array}{c}C&S&A\end{array}\right] =\left[\begin{array}{c}150+A&600-2A&A\end{array}\right]

For example :

If 0 adults attended ⇒ A = 0

C = 150 + 0 \\C = 150\\S = 600 - 2A\\S = 600

This verify the totaled receipts equation :

150($3)+600($5) = $ 3450

A ≥ 0 ⇒ If A = 0 ⇒ C = 150

C = 150 is the minimum children attendance

From the equation :

S = 600 -2A

S ≥0

600 - 2A ≥ 0

600 ≥ 2A

300≥ A

A is restricted to the interval [ 0, 300]

When A = 0 ⇒ C = 150

When A = 300 ⇒C = 150 + A = 150 + 300 = 450

Children ∈ [ 150,450]

With C being an integer number (including 0)

Also S and A are integer numbers (including 0)

7 0
3 years ago
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