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-BARSIC- [3]
3 years ago
14

Solve the equation: 2 (x + 2x) - 36 A) X=-18 B) x = 18 cx = -6 D) x = 6

Mathematics
1 answer:
bazaltina [42]3 years ago
5 0
<h2><u>Answer:</u></h2><h2>\boxed{x=6}<u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Divide both sides by 2:</h3>
  • 2 ÷ 2= Cancels Out
  • 36 ÷ 2=18

<em>  - We do this first because we need the get rid of the parenthesis in order to solve this like a regular problem. In this case the only way to do so was to divide by 2 to separate the Number/Variable from the parenthesis. </em>

<u>Equation at the end of Step 1:</u>

  • <u />x+2x=18<u />

<h3>2.) Combine x and 2x:</h3>
  • x+2x=3x

<em>  - We do this because we can't have 2 variables at the end of the equation so it's best to just combine them. </em>

<u>Equation at the end of Step 2:</u>

  • <u />3x=18<u />
<h3></h3><h3>3.) Divide both sides by 3:</h3>
  • 3x ÷ 3=x
  • 18 ÷ 3=6

<em>  - We divided for the last step since their was 1 variable connected by a number and another number on the opposite side of the equal. </em>

<em></em>

______________________________

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How many positive four-digit integers are multiples of 5 and less than 4,000
Volgvan

Answer:

  Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600

Explanation:

 Lowest four digit positive integer = 1000

 Highest four digit positive integer less than 4000 = 3999

 We know that multiples of 5 end with 0 or 5 in their last digit.

 So, lowest four digit positive integer which is a multiple of 5 = 1000

 Highest four digit positive integer less than 4000 which is a multiple of 5  = 3995.

 So, the numbers goes like,

       1000, 1005, 1010 .....................................................3990, 3995

 These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.

          An = a + (n-1)d  

           3995 = 1000 + (n-1)x 5

           (n-1) x 5 = 2995

           (n-1) = 599

            n = 600

 So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600

6 0
3 years ago
Let a=3/5 and let b=2/3. Compute a^2b^-3.
Amanda [17]

Answer: 81/100



Step-by-step explanation:

I don't guarantee you I am right but..

first, solve for the exponents after substituting the numbers in

3/5 x 3/5 is 9/25

since b's exponent is negative, you change the fraction into its reciprocal and then do it with the exponent but positive

2/3^-3 to 3/2^3 and 3/2 x 3/2 is 9/4

then you mutiply both numbers to get 9/4 x 9/25 is 81/100

7 0
2 years ago
Which is the standard form of the equation of the parabola shown in the graph?
djverab [1.8K]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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Five workers dig a trench 5 yards long in 5 hours. How many workers are needed to dig a 100 yards long in 100 hours?
Pavlova-9 [17]

I think it would require 100 workers since 1 worker digs up 1 yard.

Hope this helps.

7 0
2 years ago
Solve the exponential question . Leave your answer as a fraction
Doss [256]

Step-by-step explanation:

problem → 2^x = 4, solve for x

⇒2^x=4

⇒2^x=2^2

⇒x=2

7 0
3 years ago
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