Solve the equation: 2 (x + 2x) - 36 A) X=-18 B) x = 18 cx = -6 D) x = 6

Mathematics

1 answer:

bazaltina [42]3 years ago

5 0

<h2><u>Answer:</u></h2><h2> $\boxed{x=6}$ <u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

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<h3>1.) Divide both sides by 2:</h3>

$2$ ÷ $2=$ Cancels Out

$36$ ÷ $2=18$

<em> - We do this first because we need the get rid of the parenthesis in order to solve this like a regular problem. In this case the only way to do so was to divide by 2 to separate the Number/Variable from the parenthesis. </em>

<u>Equation at the end of Step 1:</u>

<u /> $x+2x=18$ <u />

<h3>2.) Combine x and 2x:</h3>

$x+2x=3x$

<em> - We do this because we can't have 2 variables at the end of the equation so it's best to just combine them. </em>

<u>Equation at the end of Step 2:</u>

<u /> $3x=18$ <u />

<h3></h3><h3>3.) Divide both sides by 3:</h3>

$3x$ ÷ $3=x$

$18$ ÷ $3=6$

<em> - We divided for the last step since their was 1 variable connected by a number and another number on the opposite side of the equal. </em>

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The number 64 has the property that it is divisible by its units digit. How many whole numbers between 10 and 50 have this prope

sineoko [7]

Answer:

$\large \boxed{17}$

Step-by-step explanation:

Let's call the numbers "<em>tu</em>", where<em> t</em> is the tens digit and <em>u</em> is the units digit.

We can solve this by the "brute force" method — examining each number to see if it satisfies the conditions.

$\begin{array}{cccl}\mathbf{u}&\mathbf{tu}& \textbf{Divisible by u} & \\0 &20, 30, 40 & 0 & \text{Division by zero is impossible}\\1 & 11, 21, 31, 41 & 4& \text{All numbers are divisible by one}\\2 & 12, 22, 32, 42 & 4 & \text{All even numbers are divisible by two}\\3 & 13, 23, 33, 43 & 1 &\text{Only 33 is divisible by three}\\4 & 14, 24, 34, 44 & 2 & \text{Only 24 and 44 are divisible by four}\\5 & 15, 25, 35, 45 & 4 & \text{Numbers ending in 5 are divisible by five}\\\end{array}$

$\begin{array}{cccl}6 & 16, 26, 36, 46 & 1 & \text{Only 36 is divisible by six}\\7 & 17, 27, 37, 47 & 0 & \text{None of the numbers is divisible by seven}\\8 & 18, 28, 38, 48 & 1 & \text{Only 48 is divisible by eight}\\9 & 19, 29, 39, 49 & 0 & \text{None of the numbers is divisible by nine}\\& \textbf{TOTAL =} &\mathbf{17}& \\\end{array}\\\text{$\large \boxed{\mathbf{17}}$ numbers between 10 and 50 are divisible by their units digit}$