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Veronika [31]
3 years ago
10

Use Quadratic Formula 2x2 + 10x = -11 hth24

Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

Step-by-step explanation:

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Use compatible numbers to estimate the quotient <br> 252÷3
ICE Princess25 [194]

Answer:

The value of the given expression is 84.

Step-by-step explanation:

The given expression is

\frac{252}{3}

The number 252 can be written as 240+12, because 24 can easily divisible by 3.

The compatible numbers are 240 and 12

\frac{252}{3}=\frac{240+12}{3}

\frac{252}{3}=\frac{240}{3}+\frac{12}{3}

\frac{252}{3}=80+4

\frac{252}{3}=84

Therefore the value of the given expression is 84.

4 0
3 years ago
What is the lowest common denominator of the following set of fractions: 1/6 , 13/27 , 4/5 , 3/10 , 2/5 ?
Serga [27]

Answer:

LCD = 270

Equivalent Fractions with the LCD

1/6 = 45/270

13/27 = 130/270

4/5 = 216/270

3/10 = 81/270

2/5 = 108/270

3 0
3 years ago
PLEASE HELP NOW!!!
Luden [163]

9514 1404 393

Answer:

  sometimes

Step-by-step explanation:

4 + 7 = 11 . . . not a multiple of 7

28 + 7 = 35 . . . a multiple of 7

If you add a multiple of 4 and a multiple of 7, the sum is <u>sometimes</u> a multiple of 7.

__

It will be a multiple of 7 when the multiple of 4 used is a multiple of 7, such as 4×7 or 4×14 or 4×21, for example.

5 0
2 years ago
Giving brainliest to the answer who gives step by step examples clearly!
Anarel [89]

<em>Hi there!</em>

<em>This should be easy,lol!</em>

<em>Answer:</em>

<em />\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }<em> (Decimal: -221.702503)</em>

<em />\sqrt[3]{162} = \boxed{162 \sqrt{3} }<em> (Decimal: 280.592231)</em>

<em />\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}<em />

<em>Sorry bout the explanation thingy. Their really long -.-!</em>

<em>But the last one is short so i'll put it for you!</em>

<em>Step-by-step explanation:</em>

<em>∴!For the last one!∴</em>

<em />\sqrt[3]{-1000x^4}<em />

<em>Simplifies to:</em>

<em />= - 1732.050808 * x^4<em />

<em />= - 1732.050808 * ( x * x * x * x)<em> </em>

<em />= - 1732.050808x^4<em />

<em>Have a great day/night!</em>

7 0
3 years ago
Read 2 more answers
I need help with this practice problem solving This is trigonometry from my ACT prep guide
Novay_Z [31]

Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

f(x)=A\cos (\frac{2\pi}{T}x)+b

In the given case, you have:

A = 4

T = 3π/4

b = -3

By replacing you obtain:

\begin{gathered} f(x)=4\cos (\frac{2\pi}{\frac{3\pi}{4}}x)-3 \\ f(x)=4\cos (\frac{8}{3}x)-3 \end{gathered}

Hence, the answer is:

f(x) = 4cos(8/3 x) - 3

6 0
1 year ago
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