-10v^9+8v^6+2v^5
10=5*2
8=2^3
2=2
The common factor is 2 and its least exponent is 1
The least exponent for the variable v is 5
Then, the GFC of the polynomial is 2v^5
Factoring:
2v^5 [ -(10v^9)/(2v^5)+(8v^6)/(2v^5)+(2v^5)/(2v^5) ] =
2v^5 (-5v^(9-5)+4v^(6-5)+1) =
2v^5 (-5v^4+4v+1)
Answer:
, x = 6 ton
Step-by-step explanation:
The truck can be filled with a total of 20 ton.
There are already 14 ton inside the truck, so if we call x the weight of goods that we can still add into the truck, we know that (x+14) must be equal at most at 20. Therefore, the inequality becomes:

Solving it, we find

which means that the most amount of goods that could be added to the truck is 6 tons.
Answer:
11.1d + 3.2h - 15
Step-by-step explanation:
Answer:
7.72 * 10^15
Step-by-step explanation:
8*10^15 - 2.8*10^14 = 7.72 * 10^15
The answer is option B, if this helped mark me the brainiest!!