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Sever21 [200]
2 years ago
15

If in quadrilateral ABCD, AB = DC and BC = DA, then diagonals AC and BD Select one:

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
5 0

Answer:

<em>It's </em><em>B</em><em>, the diagonals bisect each other</em>

Step-by-step explanation:

If they were equal, it would have to be a rectangle. If they were perpendicular, it would have to be a sqaure.

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\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;

\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}

\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}

\qquad \sf  \dashrightarrow  \:m =  - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)

\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~

\qquad \sf  \dashrightarrow \:y =  - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :

\qquad \sf  \dashrightarrow \:y <  - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

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