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3 years ago

Write your answer with no space and any fraction with “/“

Mathematics

1 answer:

andrew11 [14]3 years ago

3 0

Answer:

y= 3x-1

Step-by-step explanation:

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Plz help due tomorrow if correct ill give brailiest

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C) the left side of the equation should be -15 + 3r after distributing.

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The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius r?

nydimaria [60]

Volume of the cone = (1/3) pi r^2 h

h = 2r so substituting for h:-

V = (1/3) pi r^2 * 2r

V = (2/3) pi r^3

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15= x over 6 - 1

Diano4ka-milaya [45]

15 + 1 = x/6
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Answer: A)

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3 years ago

Read 2 more answers

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

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3 years ago

A graph is constructed of the length of the side of a square compared to the area of a square. what would the function rule be t

sergeinik [125]

Based on the given description above, it is said that the graph is made of the length of the side of a square. By definition, a square has equal sides, and the area of getting the square is A=s^2. Therefore, the function rule for this to find the area for any given side length would be y = x^2. Given the y is the area of the graph and x is the length of the side. Hope this answer helps.

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3 years ago