Answer:
Part A: A(m(t)) = π(81t²); Part B: 1017.36
Step by step explanation:
Part A:
To find A(m(t)), we substitute our value for m(t), 9t, in place of m:
A(m(t)) = πm² = π(9t)² = π(81t²)
A(m(t)) = π(81t²)
Part B:
Substitute 2 in for t:
A(m(2)) = π(81(2²)) = π(81(4)) = 3.14(324) = 1017.36
Is there more because with out it we can’t understand what it means
Answer:
The number of test required is: 55
Explanation:
Using combination formula:
n!/x!(n-x)!
= 11!/2!(9)!
= 55
Answer:
399/1234
Step-by-step explanation:
The relative frequency is the fraction (ratio) of sophomores to total students.
There are 399 sophomores, and 1234 total students.
So, the relative frequency is 399/1234
0.92857142857
or about 92 cents per kilogram
