Given: cos(3x – Pi) = Negative StartFraction StartRoot 3 EndRoot Over 2 EndFraction, where 0 ≤ x < 180° Which values represen
t the solutions to the equation? {10°, 110°, 130°} {20°, 100°, 140°} {30°, 330°, 390°} {60°, 300°, 420°}
1 answer:
Answer:
Step-by-step explanation:
Given the expression cos(3x-π) = -√3/2, we are to find the values of x that represent the solutions to the equation.
cos(3x-π) = -√3/2
take inverse cos of both sides
cos⁻¹[cos(3x-π)] = cos⁻¹[-√3/2]
3x-π = cos⁻¹[-√3/2]
3x-π = -30°
since 180° = π rad
Hence;
3x- 180° = -30°
3x = -30°+ 180°
3x = 150°
x = 150°/3
x = 50°
Since cos is negative in the first second and 3rd quadrant;
3x-180° = -30°
In the second quadrant;
3x-180° = 180-30
3x - 180 = 150
3x = 150+180
3x = 330
x = 110°
In the third quadrant;
3x-180° = 270+30
3x - 180 = 300
3x = 300+180
3x = 480
x = 480/3
x = 160
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A 69:92
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The answer would be -4 1/10
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<h3><u>For the 2nd part</u></h3>
<u />![\rightarrow \sf \dfrac{32}{48} = \dfrac{30}{y}](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20%5Cdfrac%7B32%7D%7B48%7D%20%3D%20%5Cdfrac%7B30%7D%7By%7D)
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I know this isnt an answer, but where is graph B and C?
M+5 is the correct answer