I believe it would be C not 100% sure but hope this helped! :)
Answer:
Step-by-step explanation:
Let us denote probability of spoilage as follows
Transformer spoilage = P( T ) ; line spoilage P ( L )
Both P ( T ∩ L ) .
Given
P( T ) = .05
P ( L ) = .08
P ( T ∩ L ) = .03
a )
For independent events
P ( T ∩ L ) = P( T ) x P ( L )
But .03 ≠ .05 x .08
So they are not independent of each other .
b )
i )
Probability of line spoilage given that there is transformer spoilage
P L/ T ) = P ( T ∩ L ) / P( T )
= .03 / .05
= 3 / 5 .
ii )
Probability of transformer spoilage but not line spoilage.
P( T ) - P ( T ∩ L )
.05 - .03
= .02
iii )Probability of transformer spoilage given that there is no line spoilage
[ P( T ) - P ( T ∩ L ) ] / 1 - P ( L )
= .02 / 1 - .08
= .02 / .92
= 1 / 49.
i v )
Neither transformer spoilage nor there is no line spoilage
= 1 - P ( T ∪ L )
1 - [ P( T ) + P ( L ) - P ( T ∩ L ]
= 1 - ( .05 + .08 - .03 )
= 0 .9
Answer:
621
629
Step-by-step explanation:
We know that
sin
(
x
+
y
)
=
sin
x
cos
y
+
sin
y
cos
x
If
cos
x
=
8
17
and
sin
y
=
12
37
We can use,
cos
2
x
+
sin
2
x
=
1
and
cos
2
y
+
sin
2
y
=
1
To calculate
sin
x
and
cos
y
sin
2
x
=
1
−
cos
2
x
=
1
−
(
8
17
)
2
=
225
17
2
sin
x
=
15
17
cos
2
y
=
1
−
sin
2
y
=
1
−
(
12
37
)
2
=
1225
37
2
cos
y
=
35
37
so,
sin
(
x
+
y
)
=
15
17
⋅
35
37
+
12
37
⋅
8
17
=
621
629
Answer link
Shwetank Mauria
Nov 22, 2016
sin
(
x
+
y
)
=
621
629
or
−
429
629
depending on the quadrant in which sine and cosine lie.
Explanation:
Before we commence further, it may be mentioned that as
cos
x
=
8
17
,
x
is in
Q
1
or
Q
4
i.e.
sin
x
could be positive or negative and as
sin
y
=
12
37
,
y
is in
Q
1
or
Q
2
i.e.
cos
y
could be positive or negative.
Hence four combinations for
(
x
+
y
)
are there and for
sin
(
x
+
y
)
=
sin
x
cos
y
+
cos
x
sin
y
, there are four possibilities.
Now as
cos
x
=
8
17
,
sin
x
=
√
1
−
(
8
17
)
2
=
√
1
−
64
289
=
√
225
289
=
±
15
17
and
as
sin
y
=
12
37
,
cos
y
=
√
1
−
(
12
37
)
2
=
√
1
−
144
1369
=
√
1225
1369
=
±
35
37
Hence,
(1) when
x
and
y
are in
Q
1
sin
(
x
+
y
)
=
15
17
×
35
37
+
8
17
×
12
37
=
525
+
96
629
=
621
629
(2) when
x
is in
Q
1
and
y
is in
Q
2
sin
(
x
+
y
)
=
15
17
×
−
35
37
+
8
17
×
12
37
=
−
525
+
96
629
=
−
429
629
(3) when
x
is in
Q
4
and
y
is in
Q
2
sin
(
x
+
y
)
=
−
15
17
×
−
35
37
+
8
17
×
12
37
=
525
+
96
629
=
621
629
(4) when
x
is in
Q
4
and
y
is in
Q
1
sin
(
x
+
y
)
=
−
15
17
×
35
37
+
8
17
×
12
37
=
−
525
+
96
629
=
−
429
629
Hence,
sin
(
x
+
y
)
=
621
629
or
−
429
629
Answer:
Since all the three sides of the triangle are of equal length, we can find the perimeter by multiplying the length of each side by 3. 20 + 20 + 20 = 3 × 20 = 60 cm.
Answer:
y=2x-6
Step-by-step explanation:
Parallel functions are functions with the same slopes but are in different positions on the coordinate plane (for this case it means that they have different y- intercepts)
So this means that the function will have a slope of 2
To find the equation we must plug in the value (1, -4) and find the new y-intercept(c)
(-4)= 2(1)+c
-4-2=c
-6=c
This means that the parallel function that goes through the point (1,-4) is
y=2x-6
