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arlik [135]
2 years ago
9

In right △ABC , the right angle is at C, m∠A=30∘ , and AC=5√ 5 units.

Mathematics
1 answer:
Makovka662 [10]2 years ago
6 0

Answer:

5\sqrt{15}+5\sqrt{5}

Step-by-step explanation:

The core uses the value of the Pythagorean theorem and special angles.

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Find a percent of change in attitude is a weather balloon moves from 50 feet 295 feet describe the percent of change as an incre
puteri [66]

Answer: 90% increase

Step-by-step explanation:

6 0
2 years ago
A family wants to build a rectangular garden on one side of a barn. If 600 feet of fencing is available to use, then what is the
vovangra [49]

Answer: (A) A=300l-l^{2}

               (B) Length varies between 1 and 150

               (C) Largest area is 22500ft²

Step-by-step explanation: Suppose length is l and width is w.

The rectangular garden has perimeter of 600ft, which is mathematically represented as

2l+2w=600

Area of a rectangle is calculated as

A=lw

Now, we have a system of equations:

2l+2w=600

A=lw

Isolate w, so we have l:

2w=600-2l

w = 300 - l

Substitute in the area equation:

A = l(300 - l)

A = 300l - l²

(A) <u>Function of area in terms of length is given by </u><u>A = 300l - l²</u>

(B) The practical domain for this function is values between 1 and 150.

(C) For the largest area, we need to determine the largest garden possible. For that, we take first derivative of the function:

A' = 300 - 2l

Find the values of l when A'=0:

300 - 2l = 0

2l = 300

l = 150

Replace l in the equation:

w = 300 - 150

w = 150

Now, calculate the largest area:

A = 150*150

A = 22500

<u>The largest area the fence can enclose is </u><u>22500ft².</u>

4 0
2 years ago
A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).
juin [17]

Answer:

A. PR = 80.6 yd

B. Perimeter = 190.6 yd

Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}

PR = \sqrt{(70)^2 + (-40)^2}

PR = \sqrt{4,900 + 1,600}

PR = \sqrt{6,500}

PR = 80.6 yd (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

PQ = |50 - 10| = 40 yd

QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

Perimeter = 190.6 yd

7 0
2 years ago
Which points are separated by distance of 6 units?
sergiy2304 [10]
I think it’s b! i hope that helps!
8 0
2 years ago
Cristina has completed .4 of his test. The test has 40 questions total. if he completes 12 more how many more will he have left?
bixtya [17]

24 because she already completed four and if she completes twelve more that that will be 24 hope that helps


5 0
3 years ago
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