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igor_vitrenko [27]
3 years ago
8

I really need help with this ... I hope someone can help!

Mathematics
1 answer:
viva [34]3 years ago
4 0

9514 1404 393

Answer:

  ∠B = 53°

  ∠C = 127°

  ∠D = 127°

Step-by-step explanation:

The trapezoid is isosceles, as indicated by the hash marks on sides AD and BC. This means it is symmetrical about the vertical center-line. Angles on the right will have the same measures as the symmetrical angles on the left.

So, you know immediately that ∠B = ∠A = 53°.

Because AB ║ DC, ∠A and ∠D are supplementary. That is, ...

  ∠D = ∠C = 180° -53°

  ∠D = ∠C = 127°

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Suppose you have 48 feet of fencing to enclose a rectangular dog pen. The function
Rufina [12.5K]

Take first derivative of area function and set it to zero

da/dx=24 - 2x=0

Now it is set to zero add -2x to both side

24 - 2x = 0

24 = 2x

Now divide by 2 in both sides

12 = Width

Your width now is 12

Plug 12 into you equation like this:

24 (12) - 12^2= A

288 - 144 = A

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144 feets is the maximum area using the width 24


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3 years ago
Which statement regarding the function y=cos(x) is true?
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SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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3 years ago
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Answer:

Hi! The correct answer is x=b^2/c, c=b^2/x

Step-by-step explanation:

<em><u>~Solve the rational equation by combining expressions and isolating the variable c and b~  </u></em>

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