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forsale [732]
3 years ago
11

Find the difference: (6y3 + 17y − 3) − (4y3 − 11y + 9)

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
<span>(6y3 + 17y − 3) − (4y3 − 11y + 9)
</span>= 6y3 + 17y − 3 − 4y3 + 11y - 9
= 2y3 + 28y  - 12
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PLEASE HELP ASAP
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Cubed root of 9

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Solve for X I need help please
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Step-by-step explanation:

Angles EBC and EDC are the same. and straight lines equal 180

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67. The line contains the point (4,0) and is parallel<br> to the line defined by 3x = 2y.
olganol [36]

Answer:

y=\frac{3}{2} x-6

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form:
  • y=mx+b where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Parallel lines will always have the same slope but different y-intercepts.

<u>1) Determine the slope of the parallel line</u>

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

3x = 2y

Switch the sides

2y=3x

Divide both sides by 2 to isolate y

\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x

Now that this equation is in slope-intercept form, we can easily identify that \frac{3}{2} is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope \frac{3}{2} . Plug this into y=mx+b:

y=\frac{3}{2} x+b

<u>2) Determine the y-intercept</u>

y=\frac{3}{2} x+b

Plug in the given point, (4,0)

0=\frac{3}{2} (4)+b\\0=6+b

Subtract both sides by 6

0-6=6+b-6\\-6=b

Therefore, -6 is the y-intercept of the line. Plug this into y=\frac{3}{2} x+b as b:

y=\frac{3}{2} x-6

I hope this helps!

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3 years ago
Which is a critical point of the function f(x) = sin(2x) in the interval [0,2pi] ?
MrRissso [65]

Answer:

D   pi/4, 3pi/4

Step-by-step explanation:

Differentiate the function then equal it to zero and solve for the interval (see attached workings)

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