Answer:
Sample mean for solution 1: 19.27; sample mean for solution 2: 10.32
Step-by-step explanation:
To find the sample mean, find the sum of the data values and divide by the sample size.
For solution 1, the sum is given by:
9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7
The sample size is 10; this gives us
192.7/10 = 19.27
For solution 2, the sum is given by:
10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2
The sample size is 10, this gives us
103.2/10 = 10.32
Answer:
We need to see the expressions given
Step-by-step explanation:
Answer:
<em>Your Interquartile range (IQR) would be 19.</em>
Step-by-step explanation:
-5, 1, 3, 7, 8, 10, 32, 36
Median: 7.5
Lower quartile: 2
Upper quartile: 21
Interquartile range: 21 - 2 = 19
Answer:
13, 14, 15
Step-by-step explanation:
Let x = age of one of the siblings
Since the age of the siblings are consecutive integers, the age of the next sibling would be x + 1 and the age of the third sibling would be x + 2
x +( x +1) + (x +2) = 42
3x + 3 = 42
collect like terms and solve for x
x = 13
The age of the first sibling is 13
The age of the second sibling is x + 1 = 13 + 1 = 14
The age of the third sibling is x + 2 = 13 + 2 = 15
The coefficient of determination can be found using the following formula:
![r^2=\mleft(\frac{n(\sum ^{}_{}xy)-(\sum ^{}_{}x)(\sum ^{}_{}y)}{\sqrt[]{(n\sum ^{}_{}x^2-(\sum ^{}_{}x)^2)(n\sum ^{}_{}y^2-(\sum ^{}_{}y)^2}^{}}\mright)^2](https://tex.z-dn.net/?f=r%5E2%3D%5Cmleft%28%5Cfrac%7Bn%28%5Csum%20%5E%7B%7D_%7B%7Dxy%29-%28%5Csum%20%5E%7B%7D_%7B%7Dx%29%28%5Csum%20%5E%7B%7D_%7B%7Dy%29%7D%7B%5Csqrt%5B%5D%7B%28n%5Csum%20%5E%7B%7D_%7B%7Dx%5E2-%28%5Csum%20%5E%7B%7D_%7B%7Dx%29%5E2%29%28n%5Csum%20%5E%7B%7D_%7B%7Dy%5E2-%28%5Csum%20%5E%7B%7D_%7B%7Dy%29%5E2%7D%5E%7B%7D%7D%5Cmright%29%5E2)
Using a Statistics calculator or an online tool to work with the data we were given, we get
So the best aproximation of r² is 0.861
