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zubka84 [21]
4 years ago
15

15gal. mulch cover 5 flowerbeds how many to cover 7 flowerbeds=

Mathematics
1 answer:
shutvik [7]4 years ago
4 0
It would take 21gal to cover 7 flowerbeds. Hope this helps! :D
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6points and brainliest answer No.4
Anton [14]
It is 6 because 6x6x6=216
3 0
3 years ago
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Arnie's car used 100 cups of gasoline during a drive. He paid $3.12per gallon for gas how much did the gas cost
Alla [95]
Okay so in a gallon there are 16 cups, in this case 100 cups is equivalent to 6.25 gallons. 6.25 times 3.12= 19.5 

Therefore $19.5 is how much the gas cost!
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4 years ago
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Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
4 years ago
PLEASE PLEASE PLEASE FIND THE UNKNOWNS WILL GIVE BRAIN TYSM!!
Wittaler [7]

Answer:

Sum of the opposite pair of a cyclic quadrilateral is 180°.

c= 180-102= 78°

c= 180-102= 78°d= 180-92= 88°

 <em><u>intercepted arc</u></em>

=>2(102°)= 140+a°

a=64°

<u>Simillarly</u>

=> 2(d°)= a°+b°

b°= 112°

so ....

<u>a=64°</u>

<u>a=64°b=112°</u>

<u>a=64°b=112°c=78°</u>

<u>a=64°b=112°c=78°d=88</u>

<em><u>hope it helps you</u></em><u> </u><u>.</u><u>.</u><u>.</u><u>.</u>

4 0
3 years ago
Pls help me i will mark brainliest if you are right !
tekilochka [14]

Answer:

second option

Step-by-step explanation:

diameter= 22 cm

radius = diameter/2

=22/2

11 cm

volume of a sphere = \frac{4}{3}*pie* r^3

=\frac{4}{3} * 3.14 *11^3

=4.186666 * 1331

=5572 . 5 cubic centimeters (cm^3)

5 0
3 years ago
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