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Elan Coil [88]
3 years ago
7

What is 10x10x1908 i need this as soon as possibly

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

Answer: 190800

Step-by-step explanation:

10 • 10 = 100

Than when you multiply anything 100 you just add two 0s to the end.

100 • 1908 = 190800

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What is the value of (-4) (32)(1/4)?
Naddika [18.5K]

Answer:

it's −32

Step-by-step explanation:

my bad if u get it wrong or anything

6 0
3 years ago
Can someone help me please, with the step by step explanation ???
kvv77 [185]

Answer:

a=2

Step-by-step explanation:

8a +9=3a +19

Subtract 9 from both sides

-9=      -9

8a=3a +10

Subtract -3a from both sides

5a=10

5a=10

5a divided by both sides

5/5

10/5=2

a=2

7 0
3 years ago
Members of the swim teams at a competition want to wash their hair. The bathroom has less than 5600 liters of water and at most
klemol [59]

Yes, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.

<h3>What is inequality?</h3>

Inequality can be define as the relation of equation contains the symbol of ( ≤, ≥, <, >) instead of equal sign in an equation.

For 35 long haired and 40 short haired member.
Put this values in the given equation.

For water 70L+60S < 5600
  70 x 35 + 60 x 40
2450+2400
4850 <5600
inequality holds


For shampoo 0.02L+0.01S ≤ 1.50
0.02 x 35 + 0.01 x 40
0.7 + 0.4
1.1 < 1.50
inequality holds

Thus, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.

Learn more about inequality here:

brainly.com/question/14098842

#SPJ1


4 0
2 years ago
A basin is filled by two pipes in 12 minutes and 16 minutes respectively. Due to the obstruction of water flow after the two pip
olasank [31]

Answer:

The time duration of the two pipes restricted flow before the flow became normal is 4.5 minutes

Step-by-step explanation:

The given information are;

The time duration for the volume, V, of the basin to be filled by one of the pipe, A, = 12 minutes

The time duration for the volume, V, of the basin to be filled by the other pipe, B, = 16 minutes

Therefore, the flow rate of pipe A = V/12

The flow rate of pipe B = V/16

Due to the restriction, we have;

The proportion of its carrying capacity the first pipe, A, carries = 7/8 of the carrying capacity

The proportion of its carrying capacity the second pipe, B, carries = 5/6 of the carrying capacity

Whereby the tank is filled 3 minutes after the restriction is removed, we have;

\dfrac{7}{8} \times \dfrac{V}{12} \times t + \dfrac{5}{6} \times \dfrac{V}{16} \times t +  \dfrac{V}{12} \times 3 + \dfrac{V}{16} \times 3 = V

Simplifying gives;

\dfrac{(2\cdot t +7) \cdot V}{16}  = V

2·t + 7 = 16

t = (16 - 7)/2 = 4.5 minutes

Therefore, it took 4.5 seconds of the restricted flow before the the flow of water in the two pipes became normal

7 0
3 years ago
Read 2 more answers
Guided Practice
spin [16.1K]

Answer:

A. {–8, –2, 18}

Step-by-step explanation:

y = 5x − 2

x = −1.2 ----> y = 5(−1.2) − 2 = −6 − 2 = −8

x = 0 -----> y = 5(0) − 2 = 0 − 2 = −2

x = 4 -----> y = 5(4) − 2 = 20 − 2 = 18

7 0
3 years ago
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