Question 18 (4 points)

Mathematics

1 answer:

Licemer1 [7]2 years ago

7 0

for similar shapes, their corresponding sides will form the same proportion or ratio for any pair of corresponding sides, now, let's check the ratio of each corresponding side on these two.

$\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \qquad \cfrac{12}{45}\implies \cfrac{4}{15}~\hfill \cfrac{25}{75}\implies \cfrac{1}{3}~\hfill \cfrac{15}{36}\implies \cfrac{5}{12} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{the triangles are \underline{not} similar}}{\cfrac{4}{15}\ne \cfrac{1}{3}\ne \cfrac{5}{12}}~\hfill$

You might be interested in

Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).

Vanyuwa [196]

$L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)$

$R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R$

5 0

2 years ago

Read 2 more answers

Write an equation parallel to the given line through the given line through the given point.

Law Incorporation [45]

The format of a line equation is y = mx + b
When two lines are parallel, their 'm' variables are equal.
Knowing this, the unknown line equation, so far, would look like this:
y = 9x + b
Since we know that the line equation goes through the point (2, 7)
7 = 18 + b
b = -11
y = 9x - 11

6 0

3 years ago

What radian measure is equivalent to 900°?<br> 5n<br> 10n<br> 1/5n<br> 9n

Sergeu [11.5K]

9n is the answer to this question

3 0

2 years ago

Read 2 more answers

PLEASE HELP

Elodia [21]

Answer:

The area of the resulting cross section is $78.5\ m^{2}$