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Oxana [17]
3 years ago
12

What is a irrational number between 9.5 and 9.7

Mathematics
2 answers:
kirza4 [7]3 years ago
8 0

Answer:  \large \sqrt{91}

<u>Step-by-step explanation:</u>

An irrational number is a square root in its simplest form.

We want an irrational number between 9.5 and 9.7

                               \huge 9.5

square all sides     90.25 < x < 94.09

Answer: The square root of any number between 90.25 and 94.09 will work so there are an infinite number of possible answers. \sqrt{91}, \sqrt{92}, \sqrt{93}, \sqrt{94}

Oliga [24]3 years ago
6 0

Step-by-step explanation:

x be an irrational number between 9.5 and 9.7.

So, we consider that  x = 9.562536941412578914...

Rounding to the nearest hundredth

x = 9.56.

9.56763865854637984..... (rounded 9.57)

irrational because it has no pattern

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Answer:

0.79 sec

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where h_{0} =10 feet

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Let this be done at time t

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tatyana61 [14]

Answer:

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The place you want to round to is the thousands place. The place to the right of that is the hundreds place. If the digit in the hundreds place is 5 or more (and it is), then the rounded number will have 1 added to its thousands digit.

After making that adjustment (if necessary), all digits to the right (hundreds, tens, ones, and so on) will be set to zero.

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<em>Comment on rounding</em>

Various rounding schemes are in use. The one described above is the one usually taught in school. In real life, it has the disadvantage that it can add a bias to a set of numbers, making their total come out higher than desired. In order to counter that, a "round to even" rule is sometimes used.

In this problem, that would mean the thousands digit would only be changed on the condition it would be changed to an even digit. (Here, that rule would give the same result. The number 346500 would be rounded down to 346000, for example.)

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