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Oxana [17]
2 years ago
12

What is a irrational number between 9.5 and 9.7

Mathematics
2 answers:
kirza4 [7]2 years ago
8 0

Answer:  \large \sqrt{91}

<u>Step-by-step explanation:</u>

An irrational number is a square root in its simplest form.

We want an irrational number between 9.5 and 9.7

                               \huge 9.5

square all sides     90.25 < x < 94.09

Answer: The square root of any number between 90.25 and 94.09 will work so there are an infinite number of possible answers. \sqrt{91}, \sqrt{92}, \sqrt{93}, \sqrt{94}

Oliga [24]2 years ago
6 0

Step-by-step explanation:

x be an irrational number between 9.5 and 9.7.

So, we consider that  x = 9.562536941412578914...

Rounding to the nearest hundredth

x = 9.56.

9.56763865854637984..... (rounded 9.57)

irrational because it has no pattern

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mestny [16]

Answer:

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Therefore, the equations are equations of <u>  Perpendicular Lines .</u>

Step-by-step explanation:

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y=\dfrac{2}{5}\times x + 1    ......................Equation ( 1 )

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Slope of equation 1 = ?

Slope of equation 2 = ?

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On comparing with slope point form

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m = Slope

c = y-intercept

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Slope of equation 1 = m1 = \dfrac{2}{5}

Step 2.

Slope of equation 1 = m2 = -\dfrac{5}{2}

Step 3.

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Product of Slopes = m1 × m2 = -1

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