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Fynjy0 [20]
2 years ago
7

Two ratios that are equivalent to 2 : 9

Mathematics
2 answers:
NeTakaya2 years ago
7 0

Answer:

4 : 18, 8 : 36

Step-by-step explanation:

We multiply to find equal ratios.

2 x 2 = 4

9 x 2 = 18

4 x 2 = 8

18 x 2 = 36

We get 4 : 18, 8 : 36.

Natalka [10]2 years ago
6 0
The answer is 18,8,36
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Answer:

1. D

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Step-by-step explanation:

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2 years ago
1. Consider drawing a single card from a well shuffled 52-card deck. Let E1 be an event of getting a heart card and E2 be an eve
Paraphin [41]
<span>1) Find P(E1UE2)
E1 probability= 1/2</span>
<span>There are 26 red cards in a 52 card deck, so the probability of choosing a red card is = 26/52 = 1/2
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<span>The face cards are: Jacks, Queens, and <span>Kings. There are four suits, so in each suit there are one jack, one queen and one king. The probability is 3 x 4= 12 divided by the total number of cards.

2)</span></span><span>the probability of drawing a blue ball on the first draw: 4 /10
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6 0
3 years ago
8/15 divided by 1/3 reduce your answer
klio [65]
Here we can use fact than we can multiply fraction by inverse of fraction instead of dividing it.
Inverse of 1/3 is 3/1
Lets multiply it
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7 0
3 years ago
40% of students enjoy playing Among us. If 100 students enjoy playing Among us, how many students are there?
Luba_88 [7]

Answer:

250

Step-by-step explanation:

40%= 100

10%=25

100%= 250

6 0
2 years ago
Read 2 more answers
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Mashcka [7]
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z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

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x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
2 years ago
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