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Mademuasel [1]
2 years ago
15

What is the equation of the following line??

Mathematics
1 answer:
wolverine [178]2 years ago
5 0

Answer:

C) y = 6x is the answer.

Step-by-step explanation:

(-1/2,-3) and (0,0)

slope(m) = ( 0 + 3)/(0 + 1/2)= 3/1/2 = 6

Now,

y = mx + b

or, y = 6x + 0

so, y = 6x

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Craig earns the same amount of money each month. His telephone bill is 1/20 of his monthly earnings, and he pays a total of $720
Juliette [100K]
Answer: $1200
Explanation:
The amount of telephone bill Craig has to pay each month: $720/12= $60
His earnings each month: $60 x 20 = $1200
7 0
3 years ago
In 1956, Dwight Eisenhower became President with 58% of the vote.
denis23 [38]

Answer:

29/50

Step-by-step explanation:

8 0
3 years ago
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Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
Find the domain of (f/g)(x) when f(x)=1/x and g(x)=square root x+8
Alex_Xolod [135]

Step-by-step explanation:

all work is pictured/shown

6 0
3 years ago
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Simplify your answer
Lelechka [254]

Answer:

<h2><u>0</u></h2>

Step-by-step explanation:

If 2u-6=4, let's solve for u.

Add 6 to both sides

2u-6+6 = 4+6

Simplify

2u = 10

Divide both sides by 2

u = 5

Now, we can solve u-5

5-5 = 0

8 0
2 years ago
Read 2 more answers
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