A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
Answer:1
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :
-2*x+5-(7)<0
Step by step solution :
STEP
1
:
Pulling out like terms
1.1 Pull out like factors :
-2x - 2 = -2 • (x + 1)
Equation at the end of step
1
:
STEP
2
:
2.1 Divide both sides by -2
Remember to flip the inequality sign:
Solve Basic Inequality :
2.2 Subtract 1 from both sides
x > -1
Inequality Plot :
2.3 Inequality plot for
-2.000 X - 2.000 > 0
One solution was found :
x > -1
Step-by-step explanation:
so go to safari and look it up !!!
If we were to foil
after experieence
we know
ax²+bx+c=0
and
in form
(ax+b)(cx+d)=0
if we expand it, we get
acx²+bcx+adx+bd=0
or
(ac)x²+(bc+ad)x+(bd)=0
compare to
ax²+bx+c=0
we notice that the middle terms (x terms) are
b=(bc+ad)
so
in form
(2x-1)(1x+5)
b=bc+ad=(-1*1+2*5)=-1+10=9
b=9
or you could just expand it
It all depends on the importance of the variable its self. Its important to solve it so you know what the variable is and its important to solve one at a time because its impossible to solve a variable completely if you have two of them