Answer:
4 students scored 3 points each
7 students scored 4 points each
Step-by-step explanation:
<u>Undetermined equations
</u>
There are problems where there are not enough data to provide a unique (determined) solution. We form as many equations as possible and try to find the combination of values of the variables to fulfill all the conditions
For this question, we are assuming the grades go from 1 to 5. We know 11 students in Mrs. Wilson's group scored 40 points in all. We must find a combination of points to produce a sum of 40. We're also assuming only integer points can be scored.
To make things easier, let's find the mean value of the total scores: 40/11=3.6
If we stick to the closest integer near 3.6 we can find a quick solution. Let's think all the students scored 4. It would give a total of 44 points (4 more than required). To adjust the excess, we simply set the score of 4 students to 3 points. Our solution will be
4 students scored 3 points each: 12 points
7 students scored 4 points each: 28 points
Total: 40 points
Note: You can find more solutions apart from this one. For example, set the score of one of the 4-points students to 3. To compensate, set another one from that group to 5 points. Our new solution will be
5 students scored 3 points each: 15 points
5 students scored 4 points each: 20 points
1 student scored 5 points : 5 points
It also has a total of 40 points from 11 students
