The best method for solving the system of linear equation is by the use of algebraic methods.
The system of linear equations can be solved by using the method of simultaneous equations. Here we are given two equations and two unknown variables. We can solve the same by eliminating one of the variables and then either adding or subtracting, find the value of the other variable. Once we know the value of one variable, then we can substitute its value in any one given equation and find the second variable. This method is said to be accurate and does not involve any error.
Hence answer is : USE ALGEBRAIC METHODS
Answer:
Ashely had 30 kisses! Muah!
Step-by-step explanation:
Ratio of Ashely to Keely is 5 : 2 and we know Keely had 12. Keely represents the 2 in this ratio, and how do we get from 2 to 12? We multiply by 6. We have to multiply by 6 on the other side too then. 5 times 6 is 30, so Ashely had 30 hershey kisses.
In real life, not in ratio form, Ashely had 30 kisses and Keely had 12.
Please mark brainliest if possible, have a nice day! :)
Y + 18 = a(x + 3)^2
<span>0 + 18 = a(0 + 3)^2 </span>
<span>18 = 9a </span>
<span>2 = a
</span>
<span>y = 2(x + 3)^2 - 18 </span>
<span>0 = 2(x + 3)^2 - 18 </span>
<span>18 = 2(x + 3)^2 </span>
<span>9 = (x + 3)^2 </span>
<span>± 3 = x + 3 </span>
<span>-3 ± 3 = x </span>
<span>x = 0 or -6
</span>
<span>(0, 0) and (-6, 0)</span>
Answer:
3
−
2
=
1
3v-2=1
3v−2=1
Solve
1
Add
2
2
2
to both sides of the equation
3
−
2
=
1
3v-2=1
3v−2=1
3
−
2
+
2
=
1
+
2
3v-2+{\color{#c92786}{2}}=1+{\color{#c92786}{2}}
3v−2+2=1+2
2
Simplify
Add the numbers
Add the numbers
3
=
3
3v=3
3v=3
3
Divide both sides of the equation by the same term
3
=
3
3v=3
3v=3
3
3
=
3
3
\frac{3v}{{\color{#c92786}{3}}}=\frac{3}{{\color{#c92786}{3}}}
33v=33
4
Simplify
Solution
=
1
Step-by-step explanation:
Answer: The mean of this distribution = 61.95
The standard deviation of this sampling distribution (i.e., the standard error= 0.048
Step-by-step explanation:
Given : Data from the U.S. Department of Education indicates that 59% of business graduate students from private universities had student loans.
i.e. proportion of business graduate students from private universities had student loans : p=0.59
sample size : n=105
Then , the mean of the distribution is given by :-
∴The mean of this distribution = 61.95
Then standard deviation of this sampling distribution is given by :-
∴The standard deviation of this sampling distribution (i.e., the standard error= 0.048
