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3 years ago

Question part points submissions used solve the given differential equation by separation of variables. dx + e2xdy = 0

1 answer:

lina2011 [118]3 years ago

4 0

Try this:
if given dx+e²ˣdy=0, then
$dy=- \frac{dx}{e^{-2x}} \ =\ \textgreater \ \ \int dy=-\int e^{-2x}dx; \ =\ \textgreater \ \ y= \frac{1}{2}e^{-2x}+C;$

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Answer:

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Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

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$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

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3 years ago

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Step-by-step explanation:

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AnnyKZ [126]

Answer:

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Step-by-step explanation:

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