Answer:
{ - 2, 1 }
Step-by-step explanation:
To determine the values let y = 0, that is
(x + 2)(2x - 2) = 0 ← in standard form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
2x - 2 = 0 ⇒ 2x = 2 ⇒ x = 1
The set of values are { - 2, 1 }
Answer:
The answer is No solution
The answer would be D) dilated by a scale factor of 3
Proof :
A is at (-2, 1), A' is at (-6, 3) Try multiplying -2 by 3 = 6, 1 x 3 = 3.
I hope this makes sense and helps.
(x-3)(x-5)=35
Multiply the brackets together
x*x-5*x-3*x-3*5
x^2-8x+15=35
Move +35 to the other side. Sign changes from +35 to -35
x^2-8x+15-35=35-35
x^2-8x-20=0
(x-10)(x+2)=0
x-10=0 x+2=0
Move -10 to the other side. Sign changes from -10 to +10
x-10+10=0+10 x+2-2=0-2
x=10 x=-2
Answer: x=10
