Question

Write (-2,-4) and (-3,-3) as a Linear equation. :)

Answer 1

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

$y = mx+b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the statement we have the following points:

$(x_ {1}, y_ {1}): (- 2, -4)\\(x_ {2}, y_ {2}): (- 3, -3)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-3 - (- 4)} {- 3 - (- 2)} = \frac {-3+4} {- 3+2} = \frac {1} {- 1} = - 1$

Thus, the equation is of the form:

$y = -x + b$

We substitute one of the points:

$-3 = - (- 3) + b\\-3 = 3 + b\\-3-3 = b\\b = -6$

Finally, the equation is of the form:

$y = -x-6$

Answer:

$y = -x-6$