How many peaches are in the salad

400g of rapberries and 300g of strawberries cost £7.46. 500g of strawberries cost £4.10 work out the cost of 300g of raspberries

MAXImum [283]

Answer: £5.39

Step-by-step explanation:

500g strawberries = 4.10

100 g = 0.82

300g = 2.46

400g raspberries = 7.46 - 2.46 = 5.00

100g = 1.25

300g = 3.75

200g strawberries = 0.82 * 2 = 1.64

3.75 + 1.64 = 5.39

8 0

3 years ago

Ed turns 34 and deposits $100 at the end of each month in IRA that earns 9% interest p.A compounded monthly. Find how much will

pickupchik [31]

Answer:

FV= $123,879.85

Step-by-step explanation:

Giving the following information:

Montlhy deposit (A)= $100

Monthly interest rate (i)= 0.09/12= 0.0075

Number of periods (n)= 12*26= 312 months

To calculate the future value, we need to use the following formula:

FV= {A*[(1+i)^n-1]}/i

A= monthly deposit

FV= {100*[(1.0075^312) - 1]} / 0.0075

FV= $123,879.85

3 0

3 years ago

An honest die is rolled. If the roll comes out even (2, 4, or 6), you will win $1; if the roll comes out odd (1,3, or 5), you wi

jenyasd209 [6]

Answer:

(a) 50%

(b) 47.5%

(c) 2.5%

Step-by-step explanation:

According to the honest coin principle, if the random variable X denotes the number of heads in n tosses of an honest coin (n ≥ 30), then X has an approximately normal distribution with mean, $\mu=\frac{n}{2}$ and standard deviation, $\sigma=\frac{\sqrt{n}}{2}$ .

Here the number of tosses is, n = 2500.

Since n is too large, i.e. n = 2500 > 30, the random variable X follows a normal distribution.

The mean and standard deviation are:

$\mu=\frac{n}{2}=\frac{2500}{2}=1250\\\\\sigma=\frac{\sqrt{n}}{2}=\frac{\sqrt{2500}}{2}=25$

(a)

To not lose any money the even rolls has to be 1250 or more.

Since, μ = 1250 it implies that the 50th percentile is also 1250.

Thus, the probability that by the end of the evening you will not have lost any money is 50%.

(b)

If the number of "even rolls" is 1250, it implies that the percentile of 1250 is 50th.

Then for number of "even rolls" as 1300,

1300 = 1250 + 2 × 25

= μ + 2σ

Then P (μ + 2σ) for a normally distributed data is 0.975.

⇒ 1300 is at the 97.5th percentile.

Then the area between 1250 and 1300 is:

Area = 97.5% - 50%

= 47.5%

Thus, the probability that the number of "even rolls" will fall between 1250 and 1300 is 47.5%.

(c)

To win $100 or more the number of even rolls has to at least 1300.

From part (b) we now 1300 is the 97.5th percentile.

Then the probability that you will win $100 or more is:

P (Win $100 or more) = 100% - 97.5%

= 2.5%.

Thus, the probability that you will win $100 or more is 2.5%.

7 0

3 years ago

James drove up 6,400 feet to a camp area on a mountain to meet his friends. They walked a trail that led to the mountain summit

gregori [183]

The answer is 4900 because you add the 6,400+1,800=8,200 then you subtract the 8,200-3,300= 4,900

6 0

3 years ago

Read 2 more answers

Type the correct answer in the box. Use a comma to separate the x- and y-coordinates of each point. The coordinates of the point

MAVERICK [17]

Answer:

On a unit circle, the point that corresponds to an angle of $0^{\circ}$ is at position $(1, \, 0)$ .

The point that corresponds to an angle of $90^{\circ}$ is at position $(0, \, 1)$ .

Step-by-step explanation:

On a cartesian plane, a unit circle is

a circle of radius $1$ ,
centered at the origin $(0, \, 0)$ .

The circle crosses the x- and y-axis at four points:

$(1, \, 0)$ ,
$(0, \, 1)$ ,
$(-1,\, 0)$ , and
$(0,\, -1)$ .

Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.

When the angle is equal to $0^\circ$ , the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be $(1, \, 0)$ .

To locate the point with a $90^{\circ}$ angle, rotate the $0^\circ$ segment counter-clockwise by $90^{\circ}$ . The segment would land on the positive y-axis. In other words, the $90^{\circ}$ -point would be at the intersection of the positive y-axis and the circle. Its coordinates would be $(0, \, 1)$ .

4 0

4 years ago