(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332
Answer:
So it's going to be 3 times 2 minus 8 3 times 2 is 6 6 minus 8 is negative 2 and that's the answer.
Step-by-step explanation:
3.35 - 3.10 = .25
.25/3.35 = .0746
.0746*100 = 7.46 or 7.5 rounded
Answer:
10x + 6
Step-by-step explanation:
3x - 5 + 7x + 11
10x - 5 + 11
10x + 6
I’m not sure the answer but go into a webpage called Desmos and it will show you
