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Varvara68 [4.7K]

3 years ago

13

Help..............................

1 answer:

stich3 [128]3 years ago

4 0

4/5th i beleive..........

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Water flows straight down from an open faucet. The cross-sectional area of the faucet is 1.00 × 10 − 4 m², and the speed of the

Setler79 [48]

Answer: $A_2=0.349\times 10^{-4} m^2$

Step-by-step explanation:

Given

velocity $v_1=0.72 m/s$

Area of cross-section $A_1=1\times 10^{-4} m^2$

velocity after Falling 0.19 m

$v_2^2-v_1^2=2g\cdot h$

$v_2^2=v_1^2+2g\cdot h$

$v_2^2=(0.72)^2+2\times 9.8\times 0.19$

$v_2^2=0.518+3.724$

$v_2=\sqrt{4.24}$

$v_2=2.05 m/s$

conserving Flow

$A_1v_1=A_2v_2$

$1\times 10^{-4}\times 0.72=A_2\times 2.05$

$A_2=0.349\times 10^{-4} m^2$

8 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

Natalie Albert deposited checks totaling $1,735,97 into her savings account. She withdrew $100.00 while

givi [52]

Anything withdrawn you subtract. Then, you know the total and you know what you had. Subtract total from what you had and you will see the change.

1735.97-100=1635.97

1668.71-1635.97=32.74

7 0

2 years ago

Need help really badly please help .

Harlamova29_29 [7]

Answer:

sin s = 36 / 42 = 18 / 21 = 6/ 7

sin R = 14 / 42 = 7 / 21 = 1 / 3

cos s = 14 / 42 = 1 / 3

cos R = 36 / 42 = 6 / 7

4 0

3 years ago

What type of table has the largest area

Helen [10]

Answer:

The Rectangular Table Has The largest area of 1460 in^2

7 0

3 years ago