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Ber [7]
3 years ago
15

One liter of paint covers 100 square feet. How many gallons of paint does it take to cover a room whose walls have an area of 80

0 square meters?
Mathematics
1 answer:
mezya [45]3 years ago
8 0
1 gallon is 3.78 L
100 sq feet needs 1 L
800 sq feet needs x

100/800 = 1/x
100x = 800
x = 800/100
x = 8 L

If you use the fact that 4 L = 1 gallon then you need 2 gallons of paint. I you use the more accurate 3.78 L then
1 gallon = 3.78 L
x gallon = 8 L

3.78 x = 8*1
x = 8/3.78
x = 2.12 gallons.
 
I guess you could say that 1 gallon and 1 L would do you.
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WEEEEEEEEEEEEEEEEEEEEEEE
matrenka [14]

YOU WILL NOT FAIL, YOU SHALL PASS

Answer: w^6/9

Step-by-step explanation:

first, i evaluated the powers.

3^-2 x 1 x 1/w^-6

then, i calculated those products.

3^-2/w^-6

then, i just expressed it with a positive exponent.

w^6/3^2

finally, i evaluated that.

w^6/9

4 0
3 years ago
Read 2 more answers
f^3+11g-4hf 3 +11g−4hf, cubed, plus, 11, g, minus, 4, h when f=3f=3f, equals, 3, g=2g=2g, equals, 2 and h=7h=7h, equals, 7.
Alik [6]

Given:

The expression is:

f^3+11g-4h

The given values are f=3,\ g=2,\ h=7.

To find:

The value of the given expression for the given values.

Solution:

We have,

f^3+11g-4h

After substituting f=3,\ g=2,\ h=7, we get

f^3+11g-4h=(3)^3+11(2)-4(7)

f^3+11g-4h=27+22-28

f^3+11g-4h=49-28

f^3+11g-4h=21

Therefore, the value of the given expression is 21.

8 0
3 years ago
An arc on a circle measures 295°. The measure of the central angle, in radians, is within which range?
andrezito [222]

Answer:

3pi/2 to 2π radians

Step-by-step explanation:

The centeal angle also has 295⁰. This value is between 275⁰ (or 3×pi/2) and 360⁰ (or 2×pi).

So, the answer is: 3pi/2 to 2π radians

3 0
3 years ago
Read 2 more answers
What is the value of log 43? Use the calculator. Round your answer to the nearest tenth.
Bad White [126]

Answer:

The value of log  43is 1.633

Step-by-step explanation:

Explanation:

Suppose you know that:

\begin{array}{l}{\log 2 \approx 0.30103} \\{\log 3 \approx 0.47712}\end{array}

Then note that:

43=\frac{129}{3} \approx \frac{128}{3}=\frac{2^{7}}{3}

So

\log 43 \approx \log \left(\frac{2^{7}}{3}\right)=7 \log 2-\log 3 \approx 7 \cdot 0.30103-0.47712=1.63009

We know that the error is approximately:

\log \left(\frac{129}{128}\right)=\log 1.0078125=\frac{\ln 1.0078125}{\ln 10} \approx 0.00782 .3=0.0034

So we can confidently give the approximation:

\log 43 \approx 1.633

6 0
3 years ago
What does the number 1 in the equation mean in this context?​
Sindrei [870]

Answer:

last option at the bottom.

Step-by-step explanation:

we are told that the the equation

y = 0.73x + 1 represents the Length of the spring when a stretch force is applied,

basically y = length of spring and x = force applied.

from the graph, we can see that when stretch force = 0 (i.e x = 0)

the equation becomes y = 1.

That is to say that the spring has a length of 1 inch when stretch force is zero

(which basically is the same as the last option)

6 0
3 years ago
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