Answer:
lim
x->3. 3×(3) Sq. -4×3-15
------------------------
(3) Sq. +3-12
lim
x->3. 3×9-12-15
---------------
9+3-12
lim
x->3. 0/0(which is in determinant form)
It will take Tyrell about 4 hours.
X increases by one
y increases by 2
(5, 1) - > (x + 1, y + 2) -> (6, 3)
Answer:
2√46 + 25π/4 ≈ 33.2 . . . . m²
Step-by-step explanation:
The altitude of the triangle is given by the Pythagorean theorem. The right triangle of interest is the one that has 5√2 as its hypotenuse, and a leg of half the base shown. Then the other leg, the altitude of the triangle, is ...
h = √((5√2)² - 2²) = √46
Then the area of the triangle shown is ...
A = (1/2)bh = (1/2)(4)(√46)
A = 2√46
__
The area of the semicircle is given by the formula ...
A = (1/2)πr²
Filling in the radius shown, the area is computed as ...
A = (1/2)π(5√2/2)² = 25π/4
So, the total area of the figure is ...
total area = triangle area + semicircle area
= 2√46 + 25π/4 . . . square meters
≈ 33.2 . . . square meters
Answer:
60 students passed, and 75 appeared in examination.
Step-by-step explanation:
Let's say s is the total number of students and p is the number of students who passed.
80% of the students passed, so:
0.8 s = p
If there were 10 less passers, and 15 less students (5 less failures), then the ratio of passers to failures would be 5/1.
(p − 10) / (s − p − 5) = 5 / 1
Simplify the second equation:
p − 10 = 5 (s − p − 5)
p − 10 = 5s − 5p − 25
6p = 5s − 15
Substitute the first equation.
6 (0.8 s) = 5s − 15
4.8 s = 5s − 15
0.2 s = 15
s = 75
p = 0.8 s
p = 60
60 students passed, and 75 appeared in examination.
