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2 years ago

Luisa is a deep-sea diver. Today she descended to a depth below -21 feet. What phrase describes the distance of Luisa’s dive?

Mathematics

1 answer:

Bingel [31]2 years ago

8 0

Answer:

its B

Step-by-step explanation:

she went deeper than 21 feet so greater than 21

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There are 2.54 centimeters in 1 inch. If a pencil is 18 cm long, how many inches is it? Round to the nearest whole number.

kupik [55]

Answer:

7 Inches

Explanation:

2.54 Cm. In One Inch.
Pencil Is 18 Cm Long

Divide:

18 ÷ 2.54 = 7.08661417323

Round:

- PNW

5 0

2 years ago

Find the missing side

Wittaler [7]

Answer:

See below

Step-by-step explanation:

Remember SOHCAHTOA

Soh...

Sine = Opposite / Hypotenuse

...cah...

Cosine = Adjacent / Hypotenuse

...toa

Tangent = Opposite / Adjacent

In this case we use TOA.

tan(71) = x/34

x = tan(71) * 34

x = 98.7

7 0

2 years ago

Y=99.99+23.75(x-1) as a Y=ax+b equation

Hatshy [7]

Answer:

$y = 23.75x + 76.24$

Step-by-step explanation:

We want to rewrite

$y = 99.99 + 23.75(x - 1)$

in the form

$y = ax + b$

We expand to get:

$y = 99.99 + 23.75x - 23.75$

Regroup similar terms:

$y = 23.75x - 23.75 + 99.99$

Simplify:

$y = 23.75x + 76.24$

This is now of the form

$y = ax + b$

where a=23.75 and b=76.24

6 0

3 years ago

A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$