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2 years ago

Fast I need thsi for a test I trust you guys pleased

Mathematics

1 answer:

Bezzdna [24]2 years ago

6 0

Answer:

x=12

Step-by-step explanation:

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3 years ago

In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel

Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

Now,

change in sulfur oxide with time i.e $\frac{\textup{dS}}{\textup{dt}}$

differentiating the given relation with respect to time 't'

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = $2\times110P\frac{\textup{dP}}{\textup{dt}}$ + 20

at P = 100 and $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = 2 × 110 × 100 × 10 + 20

$2S\frac{\textup{dS}}{\textup{dt}}$ = 220020

$\frac{\textup{dS}}{\textup{dt}}$ = $\frac{\textup{220020}}{\textup{2S}}$

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

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