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2 years ago

7

In isosceles triangle RST shown below, RS = RT,

1 answer:

vodomira [7]2 years ago

6 0

Answer:

So that is your answer .....

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Which of the following figures could represent the cross section of a rectangular pyramid? Select all that apply.

Rama09 [41]

Answer:

Options C and E

Step-by-step explanation:

Option A. Circle

We can't get a cross section in the form of a circle.

Option B. Cube

We can't get a cross section in the form of a cube.

Option C. Rectangle

When we slice a rectangular pyramid parallel to the base but not through the vertex, we get a Rectangle.

Option D. Square

We can not get a square by slicing a rectangular pyramid.

Option E. Triangle

By slicing a rectangular pyramid perpendicular to the base and passing through the vertex we can get the cross section in the form of triangle.

Options C and E will be the answer.

4 0

2 years ago

John plans to practice piano at least 2 1 2 212 hours this weekend. If he practices 1 1 6 116 hours on Saturday and 1 1 4 114 ho

Irina18 [472]

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7 0

2 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

If sally has 3 apples and johnny has 17 bananas,how many is that combined?

svp [43]

Answer: 20

Step-by-step explanation: because 3+17=20

3 0

3 years ago

Read 2 more answers

Please solve this question

oee [108]

Answer:

$\frac{1}{81}$

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$

Evaluating from the inside parenthesis outwards

$(-\frac{1}{3}) ^{2}$ = - $\frac{1}{3}$ × - $\frac{1}{3}$ = $\frac{1}{9}$ , then

$(\frac{1}{9}) ^{-2}$ = $\frac{1}{9^{-2} }$ = 9² = 81 , then

$(81)^{-1}$ = $\frac{1}{81}$

4 0

2 years ago