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kkurt [141]
1 year ago
9

LMNP is rotated 180 degrees clockwise around the origin. What are the coordinates of L?

Mathematics
1 answer:
Alona [7]1 year ago
4 0

\huge\boxed{L^\prime(0, -1)}

To rotate a point around the origin by 180 degrees, multiply both parts of the coordinate point by -1. (This means you go from (x, y) to (-x, -y).)

L(0, 1)

L^\prime(0*(-1), 1*(-1))\\\boxed{L^\prime(0, -1)}

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irina1246 [14]
So the pattern is x,y so the left is x and the right is y. Just graph it
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2 years ago
What is the answer to this question ?
Arisa [49]

Answer:

4

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h(7)= 7²-1= 49-1= 48

f(h(7))= 48/3 -12

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7 0
3 years ago
A square number and a multiple of 3 have a total of 90 what r the 2 numbers
Alecsey [184]

Hello,

Let's x² the square number

and 3*y the multiple of 3.

x^2+3y=90\\\\\boxed{y=-\dfrac{1}{3} x^2+30}\\\\

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7 0
2 years ago
Flying with the wind, a small plane flew 404 mi in 2 h. Flying against the wind, the plane could fly only 386 mi in the same amo
Alika [10]

Answer: rate of the plane is 197.5 mph

rate of wind is 4.5 mph

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

Flying with the wind, a small plane flew 404 mi in 2 h. This means that the total speed with which the plane flew is (x + y) mph.

Distance = speed × time

Distance travelled by the plane while flying with the wind is

404 = 2(x + y)

Dividing both sides of the equation by 2, it becomes

202 = x + y- - - - - - - - - - - 1

Flying against the wind, the plane could fly only 386 mi in the same amount of time. This means that the total speed at which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

386 = 2(x - y)

Dividing both sides of the equation by 2, it becomes

193 = x - y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

395 = 2x

x = 395/2

x = 197.5

Substituting x = 197.5 into equation 1, it becomes

202 = 197.5 + y

y = 202 - 197.5

y = 4.5

3 0
3 years ago
Eth enlarged the triangle below by a scale of 5.
levacccp [35]

Answer:

She should have multiplied one half (4)(3.5) by 5 squared.

Step-by-step explanation:

We are given that

Base of triangle=b=4 cm

Height of triangle=h=3.5 cm

Area of triangle=\frac{1}{2}bh=\frac{1}{2}(4)(3.5) cm^2

After enlarged

Scale factor=5

New base of enlarged triangle=b'=4(5) cm

Height of enlarged triangle=h'=3.5(5) cm

Area of enlarged triangle=\frac{1}{2}4(5)(3.5\times 5)=\frac{1}{2}(4)(3.5)(5^2) cm^2

But Beth wrote

Area of enlarged triangle=\frac{1}{2}(4)(3.5)(5)=35 cm^2

She should have multiplied one half (4)(3.5) by 5 squared.

3 0
3 years ago
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