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4 years ago

Solve k + 10 less than or equal to 6. and graph the solution

Mathematics

1 answer:

aleksley [76]4 years ago

4 0

(-4)+10=6 if you add (-4) to 10
it is like subtracting 4 from 10
witch equals six

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Angle 1 and angle 2 are supplementary. angle 1 measures 3x and angle 2 measures 2x + 10. what does x equal?

posledela

Step-by-step explanation:

3x+2x+10=180

5x+10=180

5x=170

x=34

so the value of x is 34

5 0

3 years ago

The sum of three consecutive numbers (numbers in order one after another is 84. What are the three numbers? ________+ ________ +

Serggg [28]

Answer:

The answer is 27, 28, 29.

3 0

3 years ago

A bag contains 10 red marbles, 15 green marbles, and 15 blue marbles. If Dawshawn draws a marble from the bag, what is the proba

Lyrx [107]

Answer:

10/40 or a 1 in 4 chance he will grab a red marble

Step-by-step explanation:

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5 0

4 years ago

Find the value of x. give reasons to justify your answer NEED HELP ASAP!!!!

Firlakuza [10]

Answer:

$x = 34^\circ$

Step-by-step explanation:

Note that ∠TSU and ∠PSR are vertical angles. Hence:

$m\angle TSU = m\angle PSR$

∠PSR is the sum of ∠PSQ and ∠QSR. Hence:

$\displaystyle m\angle TSU = m\angle PSQ + m\angle QSR$

We know that ∠TSU measures 4<em>x</em> and ∠QSR measures 3<em>x</em>. Thus:

$(4x) = m\angle PSQ + (3x)$

Solve for ∠PSQ:

$m\angle PSQ = x$

Next, ∠PQS and ∠RQS form a linear pair. Thus:

$m\angle PQS + m\angle RQS = 180^\circ$

∠RQS measures 68°. Thus:

$m\angle PQS +(68^\circ) = 180^\circ$

Solve for ∠PQS:

$m\angle PQS = 112^\circ$

The interior angles of a triangle must total 180°. So, for ΔPQS:

$\displaystyle m\angle SPQ + m\angle PQS + m\angle PSQ = 180^\circ$

Substitute in the known values:

$(x) + (112^\circ) + (x) = 180^\circ$

Simplify:

$2x = 68^\circ$

And divide. Hence:

$x = 34^\circ$

4 0

3 years ago

2(5m^4n^-1)^3 simplify show work please

dangina [55]

Answer:

$\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}$

Step-by-step explanation:

$\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}$

8 0

4 years ago