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ale4655 [162]
3 years ago
5

When x 4 - 2x 3 - 3x 2 - 4x - 8 is divided by x - 2

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0

Answer:

\frac{x^4-2x^3-3x^2-4x-8}{x-2}=(x^3-3x-8)-\frac{28}{x-2}

Step-by-step explanation:

We are given

Dividend is

=x^4-2x^3-3x^2-4x-8

Divisor is

=x-2

now, we can use long division

so, we get

Quotient as

Q(x)=x^3-3x-10

Remainder is

R=-28

we can write as

\frac{x^4-2x^3-3x^2-4x-8}{x-2}=(x^3-3x-8)-\frac{28}{x-2}

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