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1 year ago

PLEASE HELP ME, I HAVE NO IDEA! Find an equation for the line below.

Mathematics

1 answer:

irga5000 [103]1 year ago

8 0

9514 1404 393

Answer:

y -2 = -2/3(x +4)

Step-by-step explanation:

There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.

That form is ...

y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

The two marked points are (-4, 2) and (5, -4). All we need is the slope.

The slope is given by the formula ...

m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)

m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3

Using the first point, the equation for the line can now be written as ...

y -2 = -2/3(x -(-4))

y -2 = -2/3(x +4)

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There are 120 planes on an airfield. If 75% of the planes take off, how many planes took off?

Soloha48 [4]

Answer:

You have to do 120 divided by 0.75 use a calculator

Step-by-step explanation:

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2 years ago

THE vertices of a triangle are P(-1,3), Q(2,-1), and R(5,3) choose all the congruent sides of the triangle

Ratling [72]

Answer:

PQ and QR are congruent.

Step-by-step explanation:

The length of PQ = sqrt [(2 - -1)^2 + (-1 - 3)^2]

= sqrt 25

= 5 units.

QR = sqrt [(5-2)^2 + (3 - -1)^2) ]

= sqrt 25

= 5 units.

PR = sqrt [ ( 3-3^2 + (5- -1)^2]

= sqrt 36

= 6 units.

7 0

2 years ago

A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

6 0

2 years ago

Read 2 more answers

MANUFACTURING A shoe manufacturer spends $2.50 to make sandals and $4 to make running shoes. During a typical month, they spend

jonny [76]

Answer:

200 pairs of sandals

Step-by-step explanation:

Represent the sandals with x and the running shoes with y.

In a typical month:

$Total = 2500$

In April

$Total = 3000$

Required

The number of sandals in a typical month

In a typical month:

If 1 sandal costs 2.50, then x costs 2.50x

If 1 running shoe costs 4, then y costs 4y

The total is:

$2.50x + 4y = 2500$

In April:

If 1 sandal costs 2.50, then 2x costs 5x ---- we used 2x because the pairs is doubled

If 1 running shoe costs 4, then y costs 4y

The total is:

$5x + 4y = 3000$

The equations are:

$5x + 4y = 3000$

$2.50x + 4y = 2500$

Subtract

$5x - 2.50x + 4y - 4y = 3000 - 2500$

$2.50x = 500$

$x = \frac{500}{2.50}$

$x = 200$

8 0

2 years ago

Solve for x. 6(4x+2)= 3(8x+4)

jeka57 [31]

Answer:

x = 1

Step-by-step explanation:

6(4x + 2) = 3(8x + 4)

24x + 12 = 24x + 12

x = 1

7 0

2 years ago

Read 2 more answers