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Morgarella [4.7K]
2 years ago
12

PLEASE HELP ME, I HAVE NO IDEA! Find an equation for the line below.

Mathematics
1 answer:
irga5000 [103]2 years ago
8 0

9514 1404 393

Answer:

  y -2 = -2/3(x +4)

Step-by-step explanation:

There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.

That form is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

__

The two marked points are (-4, 2) and (5, -4). All we need is the slope.

The slope is given by the formula ...

  m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)

  m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3

Using the first point, the equation for the line can now be written as ...

  y -2 = -2/3(x -(-4))

  y -2 = -2/3(x +4)

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Step-by-step explanation:

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3 years ago
The school chorus has 52 students, which represents 26% of the seventh graders. How many total students are in the seventh grade
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7 0
2 years ago
A car travels along a straight line at a constant speed of 55.0 mi/h for a distance d and then another distance d in the same di
elena-14-01-66 [18.8K]

Answer:

a. 17.03 mi/hr b. 0 mi/hr or 18.99 mi/hr c. 17.03 mi/hr

Step-by-step explanation:

Av Vel =(V1+V2)/2 =26

Av Speed =d/t=55=> d=55t1

D=d+d 2d =2(55t1)=110t1

av Vel =110ti/(t1+t2)

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