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Talja [164]
3 years ago
8

Quadrilateral CDEF is inscribed in circle A, so m arc CDE + m arc CFE= 360°. ∠CFE and ∠CDE are inscribed angles, which means tha

t their measures are _________________. So, _________________. Using the substitution property of equality, 2 ⋅ m∠CFE + 2 ⋅ m∠CDE = 360°. Using the division property of equality, divide both sides of the equation by 2, resulting in m∠CFE + m∠CDE = 180°. Therefore, ∠CFE and ∠CDE are supplementary. twice the measure of their intercepted arcs; 2 ⋅ m arc CDE= m∠CFE and 2 ⋅ arc CDE = m∠CDE twice the measure of their intercepted arcs; marc CDE= 2 ⋅ m∠CFE and arc CFE = 2 ⋅ m∠CDE one half the measure of their intercepted arcs; m arc CDE= 2 ⋅ m∠CFE and arc CFE= 2 ⋅ m∠CDE one half the measure of their intercepted arcs; 2 ⋅ m arc CDE= m∠CFE and 2 ⋅ arc CFE= m∠CDE

Mathematics
1 answer:
Dimas [21]3 years ago
5 0

Answer:

<u>one half the measure of their intercepted arcs</u>.

<u>m arc CDE= 2 ⋅ m∠CFE and arc CFE= 2. m∠CDE</u>.

Step-by-step explanation:

Quadrilateral CDEF is inscribed in circle A, so m arc CDE + m arc CFE= 360°. ∠CFE and ∠CDE are inscribed angles, which means that their measures are <u>1/2 the measure of their intercepted arcs</u>. So, <u>m arc CDE= 2 ⋅ m∠CFE and arc CFE= 2</u>. m∠CDE.

We can see the pic shown in order to understand the question.

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