Question

A rectangle has a height of x+4 and a width of x^2+3x+2.

Answer 1

Answer:

area of rectangle=(x+4)(x^2+3x+2)

Step-by-step explanation:

area of rectangle=$length\timeswidth$

area of rectangle=$(x+4)\times(x^2+3x+2)$

where, length=height=(x+4)

width=(x^2+3x+2)

area of rectangle=(x+4)(x^2+3x+4)

Answer 2

Answer:

$area=x^3+7x^2+14x+8$

Step-by-step explanation:

the area of a rectangle is:

$area = height * width$

in this case we know the following:

height:$x+4$

width: $x^2+3x+2$

so to get the area we must muliply these two expressions:

$area=(x+4)(x^2+3x+2)$

and making the operations we get:

$area=(x+4)(x^2+3x+2)\\area=x^3+3x^2+2x+4x^2+12x+8$

adding the like terms:

$area=x^3+7x^2+14x+8$

the expression $x^3+7x^2+14x+8$ is the area of the entire rectangle