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2 years ago

15

Suppose you are driving to visit a friend in another state. You are driving at an average rate of 50 miles per hour. You must dr

ive a total of 345 miles. If you have already driven 145 miles, how long will it take you to reach your destination?

1 answer:

bagirrra123 [75]2 years ago

5 0

The answer should be 3 hours and 45 minutes if i did the math in my head correctly

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△ABC is mapped to △A′B′C′ using each of the given rules.

juin [17]

Answer:

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Step-by-step explanation:

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2 years ago

Please help with one of these

LekaFEV [45]

Number 10 is Answer: y=2.5/2x+3.5

Step-by-step explanation:

The 3.5 is the y intercept because it is when x is 0. The slope is just the change in y over the change in x

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2 years ago

Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a

just olya [345]

Answer:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and $X \sim Bin(n=600, p =0.4)$

And we want this probability:

$P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10$

$n(1-p)=600*(1-0.4)=360 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=600*0.4=240$

$\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12$

And then $X \sim N (\mu = 240, \sigma= 12)$

And we are interested on the following probability:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

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3 years ago

B increased by 16 is at most 20 in equation form

Umnica [9.8K]

Answer:

$b+16\leq 20$

Step-by-step explanation:

b increased by 16 is at most 20 in equation form

increased means add

b+16

is at most means $\leq$

$b+16\leq 20$

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2 years ago

The following sequence is an arithmetic sequence. You are not shown very many terms of this sequence, but you are shown enough t

Olegator [25]

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since the difference of the first and third value is ten, each value is five more than the previous value

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3 years ago

Read 2 more answers