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vova2212 [387]
3 years ago
6

The time required to complete a job varies inversely as the number of

Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

494/22= 22.45

~ It took one person 22.45 hours to paint a wall

Therefore, the amount of time 19 people would do the job is

= 22.45 × 19

= 426.63 hours or 427 hours 3 minutes

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The base of a prism is a right triangle with a base and height measurement of 12cm and a 5cm. If the volume of the prism is 210c
bezimeni [28]

Answer:

The height is 7 cm

Step-by-step explanation:

210 × 2 = 420

12 × 5 = 60

420 ÷ 60 = 7

6 0
4 years ago
Read 2 more answers
Michelle has a jar of quarters and dimes totalling to 3.10 if there are sixteen coins in the jar how many more quarters are ther
Sav [38]
Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10

0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes

q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters

so there are (10 - 6) = 4 more quarters then dimes
5 0
3 years ago
Graph the function f(x)=3/2x−4.<br><br> Use the line tool and select two points to graph.
luda_lava [24]
The answer will be 0-4
7 0
3 years ago
Read 2 more answers
Express 2log 4 + 3log 2 as a single logarithm
jeka94

Answer:

Step-by-step explanation:

WHEN ADDING TWO LOGS TO COMPRESS THEM YOU MULTIPLY THE TERMS

LOG(4^2)(2^3)

LOG(16)(8)

LOG(128)

3 0
3 years ago
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$10000\\&#10;r=rate\to 4\%\to \frac{4}{100}\to &0.04\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &12&#10;\end{cases}&#10;\\\\\\&#10;A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;~~&#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$16010.32\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{semi-annually, thus twice}&#10;\end{array}\to &2\\&#10;t=years\to &9&#10;\end{cases}&#10;\\\\\\&#10;A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}&#10;\\\\\\&#10;A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
6 0
4 years ago
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