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Tomtit [17]
2 years ago
6

How many molecules are in 13 moles of oxygen?

Chemistry
2 answers:
natima [27]2 years ago
8 0

Answer:

mass/13of molecules .........

Anastaziya [24]2 years ago
5 0
1 mole of oxygen is 6.02 x 1023 atoms of oxygen.
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Compared with gases, liquids: A. have stronger intermolecular attractions. B. have more space between their particles. C. are mu
Fiesta28 [93]
A. have stronger intermolecular attractions.
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2 years ago
The picture below shows a warm air mass caught between two cooler air masses. What is this type of front called? Plz, I really n
pentagon [3]

An occluded front forms when a warm air mass is caught between two cooler air masses.

6 0
3 years ago
If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

5 0
3 years ago
Balancing Chemical Equation<br> Na+Br2=NaBr
solniwko [45]

Answer:

2Na + Br2 = 2NaBr

Explanation:

In order to balance a chemical equation you make the make sure both sides have the same number of atoms on each side, you do this by multiplying on both sides as if it was a algebraic equation.

Na+ Br2 = NaBr

Na × 2 = Na2

Na × 2 = Na2

Br × 2 = Br2

2Na + Br2 = 2NaBr

Hope this helps.

7 0
3 years ago
7.20g of potassium sulfate reacts with the excess oxygen gas in a single displacement reaction, how many grams of oxygen are con
skad [1K]
The balanced chemical reaction:

K2SO4 + O2 = 2KO2 + SO2

Assuming that the reaction is complete, all of the potassium sulfate is consumed. We relate the substances using the chemical reaction. We calculate as follows:

7.20 g K2SO4 ( 1 mol / 174.26 g) ( 1 mol O2 / 1 mol K2SO4 ) ( 32 g / 1 mol ) = 1.32 g O2 consumed in the reaction.
5 0
3 years ago
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