Enter the expression 14/7N+α, where α is the lowercase Greek letter alpha. Express your answer as a chemical expression.
2 answers:
Core reactions that occur:
¹⁴₇N + ⁴₂He → ¹⁷₈O + ¹₁H
<h3>Further explanation</h3>Fusion and fission reactions are reactions involving atomic nucleus reactions
Fission reaction is a nucleation division reaction by firing a particle usually neutron so that it gets smaller particles of atomic nuclei.
Example:
Uranium nuclei division reaction
²³⁵₉₂U + ¹₀n -> ⁸⁹₃₆Kr + ¹⁴⁴₅₆Ba + 3¹₀n
In this reaction, Uranium splits into Kr and Ba isotopes and releases energy and gamma radiation
Energy is generated based on the isotope mass from the beginning of the reaction and after division
A fusion reaction is a combining reaction of 2 atomic nuclei. Usually what is often used is a reaction between the hydrogen isotope that will form Helium
³₁Ti + ²₁D -> ⁴₂He + ¹₀n
Isotopes of Hydrogen Tritium and Deuterium form Helium
At the core, reaction applies the law of eternity
- 1. energy
the energy before and after the reaction is the same
- 2. atomic number
the number of atomic numbers before and after the same
- 3. mass number
the number of mass numbers before and after the same
Particles that play a role in core reactions include
alpha α particles ₂He⁴
beta β ₋₁e⁰ particles
gamma particles γ
positron particles ₁e⁰
In general, the core reaction equation can be written:
X = target core
a = particle fired
Y = new core
b = the particle produced
Q = heat energy
or can be written simply
X (a, b) Y
In the ¹⁴₇N atomic nucleus, it is shot with alpha ⁴₂He rays which produce isotopes of Oxygen and ¹₁H protons.
¹⁴₇N + ⁴₂He → ¹⁷₈O + ¹₁H
This reaction can be written down
¹⁴₇N (α, H) ¹⁷₈O
The sum of the atomic numbers and mass numbers before and after are the same
<h3>Learn more</h3>
nuclear decay reaction
Plutonium − 239
exponential decay
Keywords: Fusion and fission reactions, alpha ₂He⁴, nuclei
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<h3><u>Full Question:</u></h3>
The following compound has been found effective in treating pain and inflammation (J. Med. Chem. 2007, 4222). Which sequence correctly ranks each carbonyl group in order of increasing reactivity toward nucleophilic addition?
A) 1 < 2 < 3
B) 2 < 3 < 1
C) 3 < 1 < 2
D) 1 < 3 < 2
<h3><u>Answer: </u></h3>The rate of nucleophilic attack of carbonyl compounds is 2<3 <1.
Option B
<h3><u>Explanation. </u></h3>Nucleophilic attack is explained as the attack of an electron rich radical to a carbonyl compound like aldehyde or a ketone. A nucleophile has a high electron density, so it searches for a electropositive atom where it can donate a portion of its electron density and become stable.
A carbonyl compound is a hybridized carbon atom with a double bonded oxygen atom in it. The oxygen atom pulls a huge portion of electron density from carbon being very electropositive.
In a ketone, there are two factors that make it less likely to undergo a nucleophilic attack than aldehyde. Firstly, the steric hindrance of two carbon groups being attached with the carbonyl carbon makes it harder for the nucleophile to approach. Secondly, the electron push by the carbon groups attached makes the carbonyl carbon a bit less electropositive than the aldehyde one. So aldehydes are more reactive towards a nucleophilic addition reaction.
Answer: When the reaction reaches equilibrium, the cell potential will be 0.00 V
Explanation:
Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.
The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.
The standard emf of a cell is related to Gibbs free energy by following relation:
The Gibbs free energy is related to equilibrium constant by following relation:
For equilibrium
Thus
Thus When the reaction reaches equilibrium, the cell potential will be 0.00 V