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3 years ago

Question 3 of 10

Chemistry

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KATRIN_1 [288]3 years ago

5 0

Answer:A

Explanation:

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What is the percentage by mass of oxygen in a formula unit of sodium hydrogen carbonate (NaHCO3)?

nadezda [96]

Percent by mass of an element can be calculated as

(Total mass of the element in the formula / formula weight ) * 100

Step 1 : Find formula weight of NaHCO₃

To find formula weight of NaHCO₃, we have to add atomic masses of the elements Na, H,C and O

Formula weight of NaHCO₃ = $Na+H+C+3 (O)$

Formula weight of NaHCO₃ = $22.99+1.01+12.01+3(16)$

Formula weight of NaHCO₃ is 84.01 g

Step 2 : Use percent by mass formula

Percent by mass of oxygen = (total mass of oxygen / formula weight) * 100

Percent by mass of oxygen = $\frac{3(16)}{84.01} * 100$

Percent by mass of oxygen = 57.14%

Answer : percentage by mass of oxygen in a formula unit of sodium hydrogen carbonate (NaHCO3) is 57.14%

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3 years ago

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Write the example of solid liquid and gas separately

zysi [14]

Answer:

Solid = rocks or other hard stuff

Liquid = water or mild or other stuff likt that

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2 years ago

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I REALLY NEED HELP can someone help me please I’ll mark you brainliest! :)

Yanka [14]

Answer:

Explanation:

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3 years ago

Which of the following is not something that should be considered when creating a debt payment plan?

Svetach [21]

Answer:

a. In general, the larger the debt, the longer you should plan to take to pay it off.

When paying off debt consider the interest rates. C., and D. are just facts.

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3 years ago

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Each step in the following process has a yield of 90.0 %. CH 4 + 4 Cl 2 ⟶ CCl 4 + 4 HCl CCl 4 + 2 HF ⟶ CCl 2 F 2 + 2 HCl The CCl

Rainbow [258]

Answer:

4.86 moles of HCl

Explanation:

1. First write the balanced chemical equations involved in the process:

$CH_{4}+_4Cl_{2}=CCl_{4}+_4HCl$

$CCl_{4}+_2HF=CCl_{2}+F_{2}+_2HCl$

2. Calculate what amount of $CCl_{4}$ is formed in the first reaction.

$3.00molesCH_{4}*\frac{1molCCl_{4}}{1molCH_{4}}=3.00molesCCl_{4}$

As the yield of each reaction is 90.0%, the amount of $CCl_{4}$ produced is the following:

$3.00molesCCl_{4}*0.90=2.7molesCCl_{4}$

3. Calculate the amount of HCl produced.

$2.7molesCCl_{4}*\frac{2molHCl}{1molCCl_{4}}=5.4molesHCl$

The total amount of HCl produced with a 90.0% yield is:

$5.4molesHCl*0.90=4.86molesHCl$

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3 years ago