d = days rented for
m = miles driven for
so the cost of the car is 35 bucks a day and 45 cents or $0.45 per mile driven, let's check it out for say a few days
1st day, 3 miles......................35(1) + 0.45(3)
2nd day, 2 miles..................35(2) + 0.45(2)
3rd day, say 5 miles............35(3) + 0.45(5)
dth day, and m miles..........35d + 0.45m
so the cost function could be written as C = 35d+0.45m.
now, we know for 2 days, d = 2, it cost 166.75 bucks, so

Answer:
(a) (6, 2)
Step-by-step explanation:
The system of equations has one of them in y= form, so it lends itself to solution by substitution.
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Using the equation for y to substitute into the first equation, we have ...
2x -y = 10
2x -(-1/2x +5) = 10 . . . . . substitute for y
2x +1/2x -5 = 10 . . . . . eliminate parentheses
5/2x = 15 . . . . . . . . . add 5, collect terms
x = 6 . . . . . . . . . . . multiply by 2/5
Using the equation for y, we have ...
y = -1/2(6) +5 = -3 +5
y = 2
The solution is (x, y) = (6, 2).
A table with columns filled with pairs of numbers that have the same ratio.