I am pretty sure that it is table one because each number from the original recipe to the teachers recipe is multiplied by three.
4.5 x 10^6 = 4,500,000
2.1 x 10^8 = 210,000,000
Therefore, 4.5 x 10^6 < 2.1 x 10^8
Okay so
#1
4 for 5 would mean each single M&M is 1.25 (5/4)
9 for 25 would mean each single M&M is about 2.78 (25/9)
4 for 5 is the better deal
#2
10 for 35 is 3.50 each (35/10)
12 for 40 is about 3.34 each (40/12)
#3
85 divided by four is 21.25 meaning you'd spend about 22 cents each
the hardware store has a better deal seeing as 19 cents each is cheaper
#4
so 13 divided by 1.4 is about 9.3 so Raisin Bran has less sugar per ounce of cereal
Answer:
Option a
Step-by-step explanation:
Given that Seth just opened a checking account. His account includes an ATM card.
With ATM card
d) he can withdraw money from any ATM centre provided sufficient balance is kept in his checking account
b) he can deposit money for fixed denominations normally in multiples of 100 in the ATM centre with ATM card
c) he can give the card with pin in any shop to purchase an item instead of paying cash.
Hence b,c,d are not right answers.
a) transfer money is not possible using ATM card.
Only with netbanking transfer of money is possible
Option a is right answer
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
