Question

In a dihybrid cross for round and yellow seeds (RrYy x RrYy), what is the probability of having green and wrinkled seeds?

Answer 1

Answer:

The probability of having green and wrinkled seeds is equal to $6.25$%

Explanation:

Here R allele is dominant over r allele and Y  allele is dominant over y allele.

Thus, a green phenotype will have genotype rr

and a wrinkled phenotype will have genotype yy

The punnet square representing the cross between RrYy  and  RrYy is as follows -

RY         Ry         rY         ry

RY RRYY RRYy RrYY RrYy

Ry RRYy RRyy RrYy Rryy

rY RrYY RrYy rrYY rrYy

ry RrYy Rryy rrYy         rryy

Out of all 16 offspring, only one offspring with genotype "rryy" represents green and wrinkled seeds.

Thus,  the probability of having green and wrinkled seeds is equal to

$\frac{1}{16} * 100\\= 6.25$%

Answer 2

Answer:

Probability of green and wrinkled seeds is $\frac{1}{16}$

Explanation:

Here ,

"R" represents the allele for round seeds

and "r" represents the allele for wrinkled seeds

"Y" represents the allele for yellow seeds and

"y " represents the allele for green seeds

Thus,

Dihybrid cross for round and yellow seeds (RrYy) means that the round allele is dominant overwrinkled seeds and yellow is dominant over green color seed

RrYy * RrYy

 RY         Ry         rY       ry

RY RRYY RRYy RrYY RrYy

Ry RRYy RRyy RrYy Rryy

rY RrYY RrYy rrYY   rrYy

ry RrYy Rryy         rrYy        rryy

Round & Yellow seeds- RRYY, RRYy, RrYY, RrYY, RRYy, RrYy, RrYY, RrYy, RrYy

Round & Green seeds – RRyy, Rryy, Rryy

Wrinkled & Yellow Seeds – rrYY, rrYy, rrYY

Wrinkled &green seeds - rryy

Number of green and wrinkled seeds - 1

Probability of green and wrinkled seeds is $\frac{1}{16}$