Answer: 2√313
Step-by-step explanation:
Pythagorean theorem: a²+b²=c²
c²=a²+b²
c²=24²+26²
c²=576+676
c²=1252
c=√1252
c=2√313
Hope this helps!! :)
Please let me know if you have any question or need any further explanation
Answer:
Athena = 10,265 km
Vesta = 102,650 km
Juno = 102,650 km
Ceres = 2,053,000 km
Apollo = 1,026,500 km
Step-by-step explanation:
Athena = 20,530 / 2 = 10,256
From there, you can work out the rest by multiplying accordingly.
Hope this helps and made sense! :)
Answer:
Step-by-step explanation:
let one diagonal=x
other diagonal=3x
area=1/2 (x±3x)=3/2 x²=54
x²=54×3/2=81
x=9 cm
3x=3×9=27
sum of diagonals=x+3x=4x=4×9=36 cm
Perpendicular lines have slopes that are inverse reciprocals of each other. That would give you the new slope in your equation. After that plug (6,2) into point slope form and solve to get your final equation.
Answer:

Step-by-step explanation:
The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

Please note that the names (
) and (
) are subjective and change depending on the angle one uses in the ratio. However the name (
) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.
In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent (
) ratio.

Substitute,

Inverse operations,


Simplify,

