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Goryan [66]
3 years ago
11

You would like to create a dictionary that maps some 2-dimensional points to their associated names. As a first attempt, you wri

te the following code:
points_to_names = {[0, 0]: "home", [1, 2]: "school", [-1, 1]: "market"}

However, this results in a type error.
Describe what the problem is, and propose a solution.

Computers and Technology
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

A dictionary is a "key - value" pair data structure type. The syntax for creating a dictionary requires that the keys come first, before the values.

This problem in the question above is as a result of you interchanging the keys and values. THE KEYS MUST COME FIRST BEFORE THE VALUES

Explanation:

To solve this problem you will need to rearrange the code this way

points_to_names = {"home":[0, 0] , "school":[1, 2], "market":[-1, 1] }

See the attached code output that displays the dictionary's keys and values

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Write a program, NumberStatistics.java, that reads an unspecified number of integers. The program ends with the input 0. The pro
Lerok [7]

Answer:

Following are the program, which can be below:

import java.util.*; //defining header file

public class NumberStatistics  //defining class NumberStatistics

{

public static void main(String[] arc) //defining main method

{

int total_number=0,max_val=0,min_val=0,neg_val=0,pos_val=0,neg_count=0,pos_count=0,x; //defining variables

Scanner ox= new Scanner(System.in); //creating Scanner class Object

System.out.println("Enter positive and negative value with sign and when complete inter 0:"); //print message  

x= ox.nextInt(); //input value from user

while(x!=0) //defining loop to check input value is 0

{

total_number++; // increment value

if(total_number == 1)  //defining conditional statement to check minimum and maximum value

{

max_val = x; //assign value in max  

min_val = x;//assign value in min

}

else  //defining else block

{

if(max_val < x) //check maximum value

{

max_val = x; //assign maximum value

}

if(min_val > x) //check minimum value

{

min_val = x; //assign minimum value

}

}

if(x > 0) //input values  

{

pos_count++; //count positive value

pos_val+=x; // add positive values

}

else  

{

neg_count++;//count negative value

neg_val+=x; // add negative values

}

x = ox.nextInt(); //input values

}

// defining conditionl statement

if(total_number != 0)  // defining if block to print all value

{

System.out.println("positive value average= "+(pos_val/(double)pos_count));

System.out.println("negative values Average= "+(neg_val/(double)neg_count));

System.out.println("all values average= "+(pos_val+neg_val)/(double)total_number);

System.out.println("maximum value = "+max_val+"\n"+" minimum value = "+min_val);

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else  

{

System.out.println("no positive values found");

System.out.println("no negative values found");

}

}

}

Output:

Enter positive and negative value with sign and when complete inter 0:

12

8

04

22

-22

-5

9

0

positive value average= 11.0

negative values Average= -13.5

all values average= 4.0

maximum value = 22

minimum value = -22

Explanation:

The Description of the above java program can be described as follows:

  • In the above code first we import the package for user input, then defines the variable "total_number,max_val,min_val,neg_val,pos_val,neg_count, pos_count,x" to store the value prints its value.
  • In the next step, a scanner class object is created for user input and defines a while loop, that checks input value isn't equal to 0, inside the loop a conditional statement defines that cont and calculates all positive, negative, and all values addition.
  • At the another conditional statement is defines, that prints all value average, and also prints maximum, minimum value.
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What is a characteristic of the network layer in the OSI model allows carrying packets for multiple types of communications amon
Paladinen [302]

Answer:

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Explanation:

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Therefore, it would be the right answer.

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I think it's right. 
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Mary needs to choose the menu in order to place the text in a desired fashion around the image.
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Can you be more specific?

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