Answer:
Upper Control Limit for a c-chart = 9.1
Step-by-step explanation:
Given - construction company has just constructed 150 new apartments. An external inspector is hired to do the final checking before they are given way to prospective customers. Inspector at random selects 8 apartments and and counts how many defects are in each one them. He finds 7,3, 2, 1, 2, 5, 4, 4 defects.
To find - What will be Upper Control Limit for a C chart ?
Proof -
Upper Control Limit for a c-chart = c bar + 3(square root of c bar)
Now,
c bar = = 3.5
∴ we get
Upper Control Limit for a c-chart = 3.5 + 3(square root of 3.5)
= 3.5 + (1.87)
= 3.5 + 5.61
= 9.1
⇒Upper Control Limit for a c-chart = 9.1
Hablas español pero la verdad nose
So if the driveway is 45 feet long and he clears 6 feet per hour, we can divide 45 by 6 to find out how many hours it will take for him to clear the driveway and that is essential
45 / 6 = 7.5
45 feet / 6 feet per hour = 7.5 hours to clear the driveway
So now we know that the graph will end when he clears the driveway
If we know he will finish after 7.5 hours then find the graph that ends at the 7.5 hour mark, and that is the last one
Answer:
<em><u>1</u></em><em><u>)</u></em><em><u>8</u></em><em><u>&</u></em><em><u>3</u></em><em><u>/</u></em><em><u>4</u></em><em><u> </u></em><em><u>CUP</u></em><em><u> </u></em><em><u>FLOUR</u></em>
<em><u>2</u></em><em><u>)</u></em><em><u>26</u></em><em><u> </u></em><em><u>KIDS</u></em><em><u> </u></em><em><u>CAN</u></em><em><u> </u></em><em><u>GO</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em>
Step-by-step explanation:
1) one batch=2 1/2 cup flour
therefore batch required in 3 1/2 batch= 5/2×7/2=35/4
=8&3/4cup flour
2)No. of kids can go for $60=8
therefore,no. of kids can go in $1=8/60
Therefore,no. of kids can go in $195=8/60×195=26 kids.