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Andre45 [30]
4 years ago
5

The graph of the function above is shown below. Which of the following statements about f(x) is true? The function f(x) does not

have an inverse because its domain is not . The function f(x) has an inverse because it is one-to-one. The function f(x) does not have an inverse because it is not one-to-one. The function f(x) has an inverse because it passes the vertical line test.
Mathematics
1 answer:
faltersainse [42]4 years ago
3 0

Answer:

B

Step-by-step explanation:

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F (x) = x3 + 2, g(x) = x2 – 1, h(x) = 3x Evaluate. g(h( f ((–1))) = ?
Ilia_Sergeevich [38]
H(f(x))=3(x^2+2)

h(f(x))=3x^2+6

g(h(f(x)))=(3x^2+6)^3+2

g(h(f(-1)))=(3(-1)^2+6)^2+2

g(h(f(-1)))=(3+6)^2+2

g(h(f(-1)))=81+2

g(h(f(-1)))=83
5 0
3 years ago
If each of the following sequences is either arithmetic or geometric, continue the decimal patterns.
I am Lyosha [343]

Answer:

12.8, 11.6, 10.4, 9.2, 8.0, 6.8, 5.6

3, 1.5, 0.75, 0.375, 0.1875, 0.09375, 0.046875

Step-by-step explanation:

The first one is arithmetic as the pattern is deducting 1.2, second one is geometric as it is dividing 2.

4 0
3 years ago
150 is 55% of what number
balandron [24]
Simple, just divide the number by the percentage and you get the original number. You can check it by multiplying the original number of 272 by 55% or .55 to get 150.
150/.55 = 272
7 0
3 years ago
What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
Coach Siegel has 3/4 pounds of rocks and wants to split them amongst 5 art projects. How much rocks can go with each art project
Eduardwww [97]

Answer:

3/4 pound is 12 oz/5

Step-by-step explanation:

3/4 is the dividend 5 is the divisor

5 0
3 years ago
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