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DedPeter [7]
3 years ago
10

Need help my answer is in blue

Mathematics
1 answer:
lana [24]3 years ago
6 0
That is right points have no height width or any other value at all
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68

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All sides of a rhombus are equal.

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Are the solutions correct?
Aloiza [94]

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First one is wrong. x should be 16.

Second one is not completely visible, so cannot say.

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Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
OleMash [197]

ANSWER



x=1.39 to the nearest hundredth.



EXPLANATION



We have the equation,



0=2x^2+3x-8



Which can be rewritten as



2x^2+3x-8=0

The question demands the use of the quadratic formula.

Comparing this to the general quadratic equation;

ax^2+bx+c=0


a=2,b=3,c=-8


The quadratic formula is given by;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}


We now substitute all the values in to the formula;


x=\frac{-3\pm\sqrt{(3)^2-4(2)(-8)}}{2(2)}

We simplify to obtain;

x=\frac{-3\pm\sqrt{9+64}}{4}


x=\frac{-3\pm\sqrt{73}}{4}


We now split the plus or minus sign to obtain;


x=\frac{-3-\sqrt{73}}{4}


This implies that;


x=-2.89

Or

x=\frac{-3+\sqrt{73}}{4}


This will evaluate to;


x=1.39

Hence, the positive solution rounded to the nearest hundredth is

x \approx 1.39

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3 years ago
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